Logarithmic Functions
3. Properties of Logarithms
Learning outcomes
- I can apply the product rule.
- I can apply the quotient rule.
- I can apply the power rule.
- I can simplify logarithmic expressions.
- I can expand and condense logarithmic expressions.
Properties of Logarithms
Introduction to the Properties of Logarithms
Logarithms provide a powerful way to work with exponential expressions. While exponents describe repeated multiplication, logarithms determine the exponent required to produce a particular number.
The properties of logarithms allow complicated logarithmic expressions to be rewritten in simpler forms.
These properties are especially useful when:
-
Simplifying mathematical expressions.
-
Combining several logarithms into a single expression.
-
Expanding logarithmic expressions into separate terms.
-
Working with scientific and engineering formulas.
-
Analysing exponential growth and decay.
Three fundamental properties form the foundation of logarithmic algebra:
-
Product Rule: Multiplication becomes addition.
-
Quotient Rule: Division becomes subtraction.
-
Power Rule: Exponents become multipliers.
These rules follow directly from the laws of exponents.
Reviewing the Meaning of a Logarithm
Recall the relationship:
aᵇ = c ⇔ logₐ(c) = b
where:
-
a is the base.
-
b is the exponent.
-
c is the result.
For real logarithms:
-
a > 0.
-
a ≠ 1.
-
c > 0.
Example
Consider:
2⁵ = 32
The equivalent logarithmic statement is:
log₂(32) = 5
The logarithm tells us which exponent produces the argument.
This connection to exponents explains why logarithmic rules work.
The Product Rule
The product rule states that the logarithm of a product equals the sum of the logarithms of its factors.
logₐ(MN) = logₐ(M) + logₐ(N)
where:
-
a > 0 and a ≠ 1.
-
M > 0.
-
N > 0.
Understanding the Rule
Suppose:
2³ = 8
and:
2⁴ = 16
Multiplying:
8 × 16 = 128
Using exponent laws:
2³ × 2⁴ = 2⁷
Therefore:
log₂(128) = 7
But:
log₂(8) = 3
and:
log₂(16) = 4
So:
log₂(8 × 16) = log₂(8) + log₂(16)
7 = 3 + 4
The product rule works because multiplying powers with the same base adds their exponents.
Deriving the Product Rule
Let:
logₐ(M) = p
and:
logₐ(N) = q
Convert to exponential form:
M = aᵖ
N = aᑫ
Multiply:
MN = aᵖ × aᑫ
Using the exponent law:
aᵖ × aᑫ = a^(p+q)
Therefore:
MN = a^(p+q)
Convert back to logarithmic form:
logₐ(MN) = p + q
Substitute the original logarithms:
logₐ(MN) = logₐ(M) + logₐ(N)
This derivation shows that the product rule is a direct consequence of the laws of exponents.
Applying the Product Rule
Worked Example: Evaluating a Product
Evaluate:
log₂(4) + log₂(8)
Apply the product rule:
= log₂(4 × 8)
= log₂(32)
Since:
2⁵ = 32
Answer = 5
Worked Example: Combining Logarithms
Simplify:
log₃(5) + log₃(9)
Apply the product rule:
= log₃(5 × 9)
= log₃(45)
The result is a single logarithmic expression.
Worked Example: Three Logarithms
Condense:
log₂(3) + log₂(5) + log₂(7)
Combine the arguments:
= log₂(3 × 5 × 7)
= log₂(105)
The product rule can be extended to any finite number of positive factors.
Expanding Products
The product rule can also be used in reverse.
Consider:
log₅(6x)
Assuming x > 0:
log₅(6x) = log₅(6) + log₅(x)
This process is called expanding a logarithmic expression.
Worked Example
Expand:
log₂(12x)
Factorise:
12x = 3 × 4 × x
Apply the product rule:
log₂(12x) = log₂(3) + log₂(4) + log₂(x)
Since:
log₂(4) = 2
Answer = log₂(3) + 2 + log₂(x)
This expansion is valid for x > 0.
The Quotient Rule
The quotient rule states that the logarithm of a quotient equals the difference between the logarithms of the numerator and denominator.
logₐ(M/N) = logₐ(M) − logₐ(N)
where:
-
a > 0 and a ≠ 1.
-
M > 0.
-
N > 0.
Understanding the Rule
Consider:
2⁶ = 64
and:
2² = 4
Dividing:
64/4 = 16
Using exponent laws:
2⁶/2² = 2⁴
Therefore:
log₂(16) = 4
But:
log₂(64) = 6
and:
log₂(4) = 2
Thus:
log₂(64/4) = log₂(64) − log₂(4)
4 = 6 − 2
Division of powers with the same base corresponds to subtraction of exponents.
Deriving the Quotient Rule
Let:
logₐ(M) = p
logₐ(N) = q
Then:
M = aᵖ
N = aᑫ
Divide:
M/N = aᵖ/aᑫ
Using exponent laws:
M/N = a^(p−q)
Convert to logarithmic form:
logₐ(M/N) = p − q
Therefore:
logₐ(M/N) = logₐ(M) − logₐ(N)
Applying the Quotient Rule
Worked Example: Evaluating a Difference
Evaluate:
log₃(81) − log₃(9)
Apply the quotient rule:
= log₃(81/9)
= log₃(9)
Since:
3² = 9
Answer = 2
Worked Example: Combining Expressions
Condense:
log₅(20) − log₅(4)
= log₅(20/4)
= log₅(5)
Answer = 1
Worked Example: Expanding a Quotient
Expand:
log₂(x/8)
Assuming x > 0:
= log₂(x) − log₂(8)
Since:
log₂(8) = 3
Answer = log₂(x) − 3
The Power Rule
The power rule states that an exponent inside a logarithm can be moved in front as a multiplier.
logₐ(Mᵏ) = k logₐ(M)
where a > 0, a ≠ 1, M > 0, and k is any real number.
Understanding the Rule
Consider:
log₂(8³)
Since:
8 = 2³
then:
8³ = (2³)³
= 2⁹
Therefore:
log₂(8³) = 9
Using the power rule:
3log₂(8)
= 3 × 3
= 9
Both methods produce the same answer.
Deriving the Power Rule
Let:
logₐ(M) = p
Then:
M = aᵖ
Raise both sides to the power k:
Mᵏ = (aᵖ)ᵏ
Using exponent laws:
Mᵏ = a^(pk)
Convert to logarithmic form:
logₐ(Mᵏ) = pk
Since:
p = logₐ(M)
we obtain:
logₐ(Mᵏ) = k logₐ(M)
Applying the Power Rule
Worked Example: Expanding a Power
Expand:
log₃(x⁴)
For x > 0:
= 4log₃(x)
Worked Example: Evaluating an Expression
Evaluate:
3log₂(4)
Since:
log₂(4) = 2
3log₂(4) = 3 × 2
Answer = 6
Alternatively:
3log₂(4) = log₂(4³)
= log₂(64)
= 6
Worked Example: Fractional Exponents
Expand:
log₅(√x)
Assuming x > 0:
√x = x^(1/2)
Therefore:
log₅(√x) = log₅(x^(1/2))
= (1/2)log₅(x)
Worked Example: Negative Exponents
Simplify:
log₂(1/x³)
Assuming x > 0:
1/x³ = x⁻³
Therefore:
log₂(x⁻³) = −3log₂(x)
Answer = −3log₂(x)
Important Special Cases of the Power Rule
The power rule leads to several useful identities.
Logarithm of 1
Since:
a⁰ = 1
logₐ(1) = 0
Logarithm of the Base
Since:
a¹ = a
logₐ(a) = 1
Logarithm of a Power of the Base
logₐ(aᵏ) = k
For example:
log₃(3⁷) = 7
Exponential and Logarithmic Inverses
a^(logₐ(x)) = x
for x > 0.
These relationships make many logarithmic calculations easier.
Summary of the Three Main Rules
|
Rule |
Formula |
Operation |
|---|---|---|
|
Product |
logₐ(MN) = logₐ(M) + logₐ(N) |
Multiplication becomes addition |
|
Quotient |
logₐ(M/N) = logₐ(M) − logₐ(N) |
Division becomes subtraction |
|
Power |
logₐ(Mᵏ) = klogₐ(M) |
Exponents become multipliers |
For the product and quotient rules, M and N must be positive. For the power rule as written, M must be positive.
The logarithms must also use the same valid base.
Expanding Logarithmic Expressions
Expanding means rewriting a logarithm of a product, quotient, or power as separate logarithmic terms.
The usual approach is:
-
Identify products and quotients.
-
Apply the product and quotient rules.
-
Apply the power rule.
-
Simplify any logarithms that can be evaluated.
Worked Example: Product and Power
Expand completely:
log₂(8x³)
Assume x > 0.
Apply the product rule:
= log₂(8) + log₂(x³)
Apply the power rule:
= log₂(8) + 3log₂(x)
Since:
log₂(8) = 3
Answer = 3 + 3log₂(x)
Worked Example: Product, Quotient, and Power
Expand:
log₃(9x²/y⁴)
Assume x > 0 and y > 0.
Apply the quotient rule:
= log₃(9x²) − log₃(y⁴)
Apply the product rule:
= log₃(9) + log₃(x²) − log₃(y⁴)
Apply the power rule:
= 2 + 2log₃(x) − 4log₃
Final Answer:
2 + 2log₃(x) − 4log₃
Worked Example: Square Roots and Quotients
Expand:
ln(√x/y³)
Assume x > 0 and y > 0.
Rewrite the square root:
√x = x^(1/2)
Apply the quotient rule:
= ln(x^(1/2)) − ln(y³)
Apply the power rule:
= (1/2)ln(x) − 3ln
Handling Variables That May Be Negative
When expanding logarithms involving even powers, domain restrictions require special care.
For example:
log₂(x²)
is defined whenever x ≠ 0, including negative x.
Therefore, the expansion valid over the full real domain is:
log₂(x²) = 2log₂|x|
It is not generally correct to write 2log₂(x), because log₂(x) is undefined when x is negative.
Similarly:
ln(x²y⁴) = 2ln|x| + 4ln|y|
for x ≠ 0 and y ≠ 0.
Absolute values are unnecessary when the problem explicitly states that all variables are positive.
This distinction becomes especially important in advanced algebra and calculus.
Condensing Logarithmic Expressions
Condensing is the reverse of expanding.
It involves combining several logarithmic terms into a single logarithm.
The general procedure is:
-
Use the power rule to move coefficients into exponents.
-
Combine addition using the product rule.
-
Combine subtraction using the quotient rule.
-
Simplify the argument where possible.
Worked Example: Condensing Two Terms
Condense:
log₂(x) + log₂(5)
Apply the product rule:
= log₂(5x)
Valid for x > 0.
Worked Example: Coefficients and Subtraction
Condense:
3log₄(x) − 2log₄
Assume x > 0 and y > 0.
Apply the power rule:
= log₄(x³) − log₄(y²)
Apply the quotient rule:
= log₄(x³/y²)
Worked Example: Combining Three Terms
Condense:
2ln(x) + ln − 3ln(z)
Assume x, y, and z are positive.
Apply the power rule:
= ln(x²) + ln − ln(z³)
Apply the product rule:
= ln(x²y) − ln(z³)
Apply the quotient rule:
= ln(x²y/z³)
Multi-Step Expansion and Condensation
Some problems require all three rules.
Worked Example: Complete Expansion
Expand:
log₅[25x³√y/z²]
Assume x > 0, y > 0, and z > 0.
Step 1: Apply the Quotient Rule
= log₅(25x³√y) − log₅(z²)
Step 2: Apply the Product Rule
= log₅(25) + log₅(x³) + log₅(√y) − log₅(z²)
Step 3: Apply the Power Rule
= log₅(25) + 3log₅(x) + (1/2)log₅ − 2log₅(z)
Step 4: Evaluate the Constant
Since:
5² = 25
log₅(25) = 2
Final Answer
2 + 3log₅(x) + (1/2)log₅ − 2log₅(z)
Reverse Process
Starting with the expanded expression, the same rules can be applied in reverse to recover the original single logarithm.
This demonstrates that expansion and condensation are inverse algebraic processes.
Simplifying Logarithmic Expressions
Logarithmic expressions can often be simplified without a calculator.
Worked Example
Simplify:
log₂(16) + log₂(8) − log₂(4)
Apply the product and quotient rules:
= log₂[(16 × 8)/4]
= log₂(32)
Answer = 5
Worked Example
Simplify:
2log₃(9) − log₃(27)
Since:
log₃(9) = 2
log₃(27) = 3
we obtain:
2(2) − 3
Answer = 1
Alternatively:
= log₃(9²/27)
= log₃(3)
= 1
The Change-of-Base Formula
The change-of-base formula allows logarithms to be rewritten using a different base.
logₐ(x) = log(x)/log(a)
or:
logₐ(x) = ln(x)/ln(a)
where a > 0, a ≠ 1, and x > 0.
Worked Example
Evaluate:
log₄(20)
Using common logarithms:
log₄(20) = log(20)/log(4)
≈ 1.30103/0.60206
≈ 2.161
Why Change of Base Works
Let:
y = logₐ(x)
Then:
aʸ = x
Take the natural logarithm of both sides:
ln(aʸ) = ln(x)
Apply the power rule:
y ln(a) = ln(x)
Rearrange:
y = ln(x)/ln(a)
Therefore:
logₐ(x) = ln(x)/ln(a)
The change-of-base formula is itself an application of the power rule.
Simplifying Expressions with Different Bases
The product and quotient rules require logarithms with the same base.
However, the change-of-base formula can help when different bases appear.
Worked Example
Simplify:
log₂(8) + log₄(16)
Evaluate each logarithm:
log₂(8) = 3
log₄(16) = 2
Therefore:
Answer = 5
We cannot directly combine these terms using the product rule because their bases are different.
Another Example
Evaluate:
log₂(3) × log₃(8)
Using change of base:
log₂(3) = ln(3)/ln(2)
log₃(8) = ln(8)/ln(3)
Multiply:
= [ln(3)/ln(2)] × [ln(8)/ln(3)]
Cancel ln(3):
= ln(8)/ln(2)
= log₂(8)
Answer = 3
This illustrates how logarithmic properties can reveal relationships that are not immediately obvious.
Applying Logarithm Rules to Exponential Equations
Logarithmic properties are essential for solving exponential equations.
Worked Example
Solve:
3^(2x) = 50
Step 1: Take Logarithms
ln(3^(2x)) = ln(50)
Step 2: Apply the Power Rule
2x ln(3) = ln(50)
Step 3: Isolate x
x = ln(50)/[2ln(3)]
Step 4: Calculate
x ≈ 1.780
Verification
3^(2 × 1.780) ≈ 50
The result is reasonable.
Applying Logarithm Rules to Growth Models
Logarithms appear in many scientific models.
Consider exponential population growth:
P(t) = P₀e^(kt)
where:
-
P(t) is the population at time t.
-
P₀ is the initial population.
-
k is the continuous growth rate.
-
t is time.
Worked Example
A population follows:
P(t) = 500e^(0.08t)
Find when the population reaches 2000.
Step 1: Substitute
2000 = 500e^(0.08t)
Step 2: Divide
4 = e^(0.08t)
Step 3: Take Natural Logarithms
ln(4) = ln(e^(0.08t))
Step 4: Apply the Power Rule
ln(4) = 0.08t
Step 5: Solve
t = ln(4)/0.08
t ≈ 17.33
The population reaches 2000 after approximately 17.33 time units.
Logarithmic Properties in Science
The properties of logarithms are useful because they convert multiplication and powers into simpler algebraic operations.
Sound Intensity
Sound intensity level is calculated using:
L = 10log₁₀(I/I₀)
Applying the quotient rule:
L = 10[log₁₀(I) − log₁₀(I₀)]
when I and I₀ are expressed in the same positive units.
This demonstrates how a logarithmic ratio can be expanded into a difference.
Radioactive Decay
A simplified radioactive decay model is:
N(t) = N₀e^(−λt)
Taking natural logarithms:
ln[N(t)/N₀] = −λt
This form can be used to calculate decay constants or elapsed time.
Chemistry
The pH scale uses a logarithmic relationship:
pH = −log₁₀(a_H⁺)
where a_H⁺ is the dimensionless hydrogen-ion activity.
The power and quotient rules help analyse concentration ratios and changes in acidity.
Information Theory
Logarithms are used to quantify information.
For an event with probability p:
I = −log₂(p)
where I is the information content in bits.
For independent events with probabilities p and q:
−log₂(pq) = −log₂(p) − log₂(q)
Thus, the information associated with independent events adds.
Recognising Invalid Logarithm Rules
Not every algebraic operation has a corresponding logarithmic property.
The following statements are generally incorrect.
Incorrect:
logₐ(M + N) = logₐ(M) + logₐ(N)
Incorrect:
logₐ(M − N) = logₐ(M) − logₐ(N)
Incorrect:
logₐ(MN) = logₐ(M) × logₐ(N)
Numerical Counterexample
Consider:
log₂(2 + 2)
= log₂(4)
= 2
But:
log₂(2) + log₂(2)
= 1 + 1
= 2
These happen to agree, but this does not prove a general rule.
Choose a different example:
log₂(2 + 4)
= log₂(6)
≈ 2.585
However:
log₂(2) + log₂(4)
= 1 + 2
= 3
The values are different.
Therefore:
logₐ(M + N) ≠ logₐ(M) + logₐ(N)
in general.
The product rule applies to multiplication, not addition.
Choosing Between Expansion and Condensation
Different problems benefit from different forms.
|
Situation |
Recommended approach |
|---|---|
|
Simplifying a logarithm of a product |
Expand using the product rule |
|
Simplifying a logarithm of a quotient |
Expand using the quotient rule |
|
Removing an exponent from a logarithm |
Apply the power rule |
|
Combining several logarithmic terms |
Condense |
|
Solving an exponential equation |
Take logarithms and use the power rule |
|
Evaluating unfamiliar logarithmic bases |
Use change of base |
|
Simplifying a complex logarithmic fraction |
Expand or condense strategically |
|
Proving a logarithmic identity |
Transform one side using valid rules |
A useful strategy is to choose the form that makes the next algebraic step easiest.
Common Mistakes
Confusing multiplication with addition
The product rule applies to multiplication inside a logarithm, not addition.
Confusing division with subtraction
The quotient rule applies to a quotient inside a logarithm, not to subtraction inside the argument.
Applying the power rule incorrectly
The exponent becomes a multiplier outside the logarithm.
Using different bases in the product or quotient rule
The logarithms must have the same base before they can be combined directly.
Forgetting domain restrictions
Real logarithms require positive arguments.
Ignoring absolute values when expanding even powers
For example, logₐ(x²) = 2logₐ|x| for x ≠ 0.
Applying the product rule to negative factors
The real product rule requires both factors to be positive, even if their product is positive.
Forgetting to distribute coefficients
For example:
2[log(x) + log] = 2log(x) + 2log
Condensing before applying the power rule
It is often easier to move coefficients into exponents first.
Using logarithmic rules without checking equivalence
Algebraic transformations must preserve the original domain.
Rounding intermediate calculations too early
Retain sufficient precision until the final answer.
Key Terms
-
Logarithm: The exponent required to raise a given base to a specified positive value.
-
Base: The positive number, other than 1, used in a logarithmic expression.
-
Argument: The positive expression inside a logarithm.
-
Product Rule: The property that converts the logarithm of a product into a sum of logarithms.
-
Quotient Rule: The property that converts the logarithm of a quotient into a difference of logarithms.
-
Power Rule: The property that allows an exponent inside a logarithm to become a multiplier.
-
Expansion: Rewriting one logarithm as a sum or difference of simpler logarithms.
-
Condensation: Combining multiple logarithmic terms into one logarithm.
-
Logarithmic Expression: An algebraic expression containing logarithms.
-
Logarithmic Identity: A relationship involving logarithms that is valid throughout its stated domain.
-
Exponential Form: A mathematical statement written using a base raised to an exponent.
-
Logarithmic Form: An equivalent statement expressing the exponent as a logarithm.
-
Inverse Operation: An operation that reverses another operation.
-
Common Logarithm: A logarithm with base 10.
-
Natural Logarithm: A logarithm with base e.
-
Change-of-Base Formula: A formula that rewrites a logarithm using a different base.
-
Exponent Law: A mathematical rule describing operations involving powers.
-
Domain Restriction: A condition limiting allowable input values.
-
Absolute Value: The nonnegative magnitude of a real number.
-
Equivalent Expressions: Expressions that have equal values for every input in their common domain.
-
Exponential Equation: An equation containing a variable in an exponent.
-
Logarithmic Equation: An equation containing one or more logarithmic expressions.
-
Exponential Growth: Growth by a constant multiplicative factor over equal time intervals.
-
Exponential Decay: Decrease by a constant multiplicative factor over equal time intervals.
-
Continuous Growth: Exponential growth modelled using the constant e.
-
Mathematical Simplification: Rewriting an expression in a more useful equivalent form.
Key Takeaways
-
The three fundamental logarithm properties are the product rule, quotient rule, and power rule.
-
The product rule converts multiplication inside a logarithm into addition outside it.
-
The quotient rule converts division inside a logarithm into subtraction outside it.
-
The power rule converts an exponent inside a logarithm into a multiplier.
-
These rules follow directly from the laws of exponents.
-
Logarithms can be expanded into sums and differences of simpler logarithms.
-
Logarithmic expressions can also be condensed into a single logarithm.
-
Expansion and condensation are reverse processes.
-
Applying the power rule before condensing often simplifies the calculation.
-
Logarithmic properties can be used to evaluate expressions without a calculator.
-
The product and quotient rules require logarithms with the same base.
-
The arguments of real logarithms must be positive.
-
Absolute values may be necessary when expanding logarithms involving even powers of variables.
-
The change-of-base formula allows logarithms to be evaluated using common or natural logarithms.
-
Logarithmic rules are essential for solving exponential equations.
-
The properties of logarithms simplify mathematical models involving growth, decay, sound intensity, and scientific measurements.
-
There is no general logarithm rule that separates addition or subtraction inside an argument.
-
A valid logarithmic simplification must preserve mathematical equivalence and domain restrictions.
-
Mastering logarithmic properties provides the algebraic foundation for logarithmic equations, exponential modelling, and advanced calculus.
Check Your Understanding
Recall and Understanding
-
State the product, quotient, and power rules of logarithms.
-
Explain why the product rule follows from the laws of exponents.
-
Describe the difference between expanding and condensing logarithmic expressions.
-
Explain why logarithms must have the same base to use the product or quotient rule directly.
-
Explain why log₂(x²) cannot always be expanded as 2log₂(x) for every nonzero real x.
Application
-
Expand log₃(27x²), assuming x > 0.
-
Expand ln(x³/y²), assuming x > 0 and y > 0.
-
Condense 2log₅(x) + 3log₅
, assuming x > 0 and y > 0.
-
Simplify log₂(32) + log₂(4) − log₂(8).
-
Condense 3ln(a) − 2ln(b) + ln(c), assuming all variables are positive.
Analysis and Challenge
-
Expand log₂[8x⁴√y/z³] completely, assuming x, y, and z are positive.
-
Condense 2log₃(x) + (1/2)log₃
− 4log₃(z) into a single logarithm, assuming all variables are positive.
-
Prove the change-of-base formula using the power rule.
-
Solve 5^(3x−1) = 40 using logarithms, giving the answer to three decimal places.
-
A population follows P(t) = 1200e^(0.06t). Determine when it will reach 5000 and explain how the power rule is used in the solution.
Final Summary
The properties of logarithms provide a systematic way to simplify and manipulate expressions involving logarithmic functions.
The product rule transforms multiplication into addition.
The quotient rule transforms division into subtraction.
The power rule transforms exponents into multipliers.
These properties are derived from the laws of exponents and are fundamental to logarithmic algebra.
By applying the rules in reverse, several logarithmic terms can be combined into a single expression.
The same properties can be used to expand complicated logarithmic expressions into simpler components.
Logarithmic properties are also essential for solving exponential equations, working with growth and decay models, and interpreting scientific relationships.
Careful attention must be given to bases, positive arguments, domain restrictions, and valid algebraic transformations.
The central principle is that logarithms convert multiplicative and exponential relationships into additive and algebraic relationships, making complex expressions easier to simplify, analyse, and solve.