3. The Distributive Property

Learning outcomes
  • I can expand brackets using the distributive property.
  • I can distribute negative signs correctly.
  • I can simplify expressions after expansion.
  • I can recognize when distribution is required.
  • I can apply distribution in multi-step problems.

The Distributive Property

The distributive property is an important algebraic rule that allows us to remove brackets by multiplying the term outside the brackets by every term inside.

For example:

3(x + 4)

means that 3 multiplies both x and 4:

3(x + 4) = 3x + 12

This process is often called expanding brackets.

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Learning Targets

  • I can expand brackets using the distributive property.
  • I can distribute negative signs correctly.
  • I can simplify expressions after expansion.
  • I can recognize when distribution is required.
  • I can apply distribution in multi-step problems.

What Is the Distributive Property?

The distributive property tells us:

a(b + c) = ab + ac

The value outside the brackets multiplies every term inside the brackets.

For subtraction:

a(b − c) = ab − ac

For example:

5(x + 2)

Multiply 5 by x:

5 × x = 5x

Multiply 5 by 2:

5 × 2 = 10

Therefore:

5(x + 2) = 5x + 10


Why Does Distribution Work?

We can understand distribution using ordinary numbers.

Consider:

3(4 + 2)

Calculate inside the brackets first:

3(6) = 18

Now distribute instead:

3(4) + 3(2)

= 12 + 6

= 18

Both methods give the same result.

Therefore:

3(4 + 2) = 3(4) + 3(2)

The same principle works when variables are involved.


An Area Model

The distributive property can also be understood using the area of a rectangle.

Imagine a rectangle with height:

3

and total width:

x + 4

Its area is:

3(x + 4)

We can divide the rectangle into two smaller rectangles.

One has area:

3x

The other has area:

3 × 4 = 12

Therefore, the total area is:

3x + 12

So:

3(x + 4) = 3x + 12

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This provides a visual explanation of why distribution works.


Expanding Brackets

To expand brackets, multiply the term outside the brackets by every term inside.

Consider:

4(x + 5)

Multiply:

4 × x = 4x

and:

4 × 5 = 20

Therefore:

4(x + 5) = 4x + 20

Once the multiplication has been completed, the brackets are no longer needed.


Worked Example — Addition Inside Brackets

Expand:

6(x + 3)

Multiply 6 by x:

6x

Multiply 6 by 3:

18

Therefore:

6(x + 3) = 6x + 18


Worked Example — Subtraction Inside Brackets

Expand:

5(x − 4)

Multiply 5 by x:

5x

Multiply 5 by −4:

−20

Therefore:

5(x − 4) = 5x − 20

The subtraction sign stays with the term being multiplied.


Every Term Must Be Multiplied

A common mistake is multiplying only the first term.

For example:

3(x + 7)

Incorrect:

3x + 7

Correct:

3x + 21

because:

3 × x = 3x

and:

3 × 7 = 21

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A useful visual technique is to draw arrows from the outside term to each term inside the brackets.


Distributing to Several Terms

The brackets may contain more than two terms.

For example:

2(x + y + 5)

Multiply 2 by every term:

2 × x = 2x

2 × y = 2y

2 × 5 = 10

Therefore:

2(x + y + 5) = 2x + 2y + 10

The distributive property works no matter how many terms are inside the brackets.


Variables Outside the Brackets

The term outside the brackets can contain a variable.

Consider:

x(x + 4)

Distribute x:

x × x = x²

x × 4 = 4x

Therefore:

x(x + 4) = x² + 4x

Another example:

3x(x + 2)

Multiply:

3x × x = 3x²

3x × 2 = 6x

Therefore:

3x(x + 2) = 3x² + 6x


Distributing Negative Numbers

Extra care is required when the term outside the brackets is negative.

Consider:

−3(x + 4)

Multiply −3 by x:

−3x

Multiply −3 by 4:

−12

Therefore:

−3(x + 4) = −3x − 12

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Remember the multiplication rules for signs:

Positive × Positive = Positive

Positive × Negative = Negative

Negative × Positive = Negative

Negative × Negative = Positive


Negative Times Negative

Consider:

−4(x − 3)

Multiply −4 by x:

−4x

Now multiply:

−4 × −3 = +12

Therefore:

−4(x − 3) = −4x + 12

The second sign changes because multiplying two negative numbers produces a positive number.


Worked Example — Negative Distribution

Expand:

−5(2x − 7)

Multiply −5 by 2x:

−10x

Multiply −5 by −7:

+35

Therefore:

−5(2x − 7) = −10x + 35

This is an important situation where careful attention to signs is essential.


A Negative Sign Before Brackets

Sometimes there is only a negative sign before the brackets.

For example:

−(x + 5)

A negative sign can be thought of as multiplication by:

−1

Therefore:

−1(x + 5)

Distribute −1:

−x − 5

So:

−(x + 5) = −x − 5


Subtracting an Entire Expression

Consider:

10 − (x + 3)

The negative sign applies to everything inside the brackets.

Rewrite:

10 − x − 3

Combine the constants:

7 − x

Therefore:

10 − (x + 3) = 7 − x


Subtracting an Expression with a Negative Term

Consider:

12 − (2x − 5)

Distribute the negative sign:

12 − 2x + 5

Notice that:

−(−5) = +5

Now combine constants:

17 − 2x

Therefore:

12 − (2x − 5) = 17 − 2x

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Expand and Simplify

Often, expanding brackets is only the first step.

After expansion, we may need to combine like terms.

Consider:

3(x + 4) + 2x

First expand:

3x + 12 + 2x

Now combine like terms:

3x + 2x = 5x

Therefore:

3(x + 4) + 2x = 5x + 12


Worked Example — Expand and Simplify

Simplify:

4(x + 2) + 3x

Expand:

4x + 8 + 3x

Combine like terms:

4x + 3x = 7x

Therefore:

4(x + 2) + 3x = 7x + 8


Worked Example — Including Subtraction

Simplify:

5(x − 3) + 2x

Expand:

5x − 15 + 2x

Combine like terms:

5x + 2x = 7x

Therefore:

5(x − 3) + 2x = 7x − 15


Worked Example — Negative Distribution and Simplifying

Simplify:

8x − 3(x + 2)

Distribute −3:

8x − 3x − 6

Combine like terms:

8x − 3x = 5x

Therefore:

8x − 3(x + 2) = 5x − 6

The negative sign is part of the number being distributed.


Two Sets of Brackets

Sometimes an expression contains more than one set of brackets.

Consider:

2(x + 3) + 4(x − 1)

Expand the first brackets:

2x + 6

Expand the second brackets:

4x − 4

Now write everything together:

2x + 6 + 4x − 4

Combine like terms:

2x + 4x = 6x

and:

6 − 4 = 2

Therefore:

2(x + 3) + 4(x − 1) = 6x + 2

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Worked Example — Two Brackets with Subtraction

Simplify:

5(x + 2) − 2(x − 3)

Expand the first brackets:

5x + 10

Distribute −2 through the second brackets:

−2x + 6

Now:

5x + 10 − 2x + 6

Combine like terms:

5x − 2x = 3x

10 + 6 = 16

Therefore:

5(x + 2) − 2(x − 3) = 3x + 16


Distribution with Several Variables

The distributive property works with several variables.

Consider:

3x(2x + y − 4)

Multiply 3x by every term:

3x × 2x = 6x²

3x × y = 3xy

3x × −4 = −12x

Therefore:

3x(2x + y − 4) = 6x² + 3xy − 12x

The same rule applies:

Multiply every term inside the brackets.


Recognizing When Distribution Is Required

Distribution is needed when a number, variable, or term multiplies an entire group.

Examples include:

3(x + 5)

−2(x − 7)

x(x + 4)

5a(2a + 3)

You may also need distribution when subtracting an entire expression:

8 − (x + 2)

In each case, the multiplication applies to every term in the group.


When Distribution Is Not Required

Not every set of brackets needs to be expanded immediately.

For example:

3(x + 4)

may sometimes be more useful in its factored form.

If you only need to evaluate it when:

x = 2

you could calculate:

3(2 + 4)

= 3(6)

= 18

There is no requirement to expand first.

Whether expansion is useful depends on the problem.


Equivalent Expressions

Expansion creates an expression that looks different but has the same value.

For example:

4(x + 3)

and:

4x + 12

are equivalent expressions.

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We can check this by choosing a value.

Let:

x = 5

First expression:

4(5 + 3)

= 4(8)

= 32

Second expression:

4(5) + 12

= 20 + 12

= 32

Both expressions give the same result.


Distribution and Factoring Are Opposites

Distribution expands an expression:

3(x + 4) → 3x + 12

Factoring reverses the process:

3x + 12 → 3(x + 4)

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These are opposite ways of writing the same relationship.

This becomes especially useful later when working with equations, quadratics, and algebraic fractions.


Distribution in Equations

The distributive property is also important when solving equations.

Consider:

3(x + 2) = 18

One method is to expand:

3x + 6 = 18

Subtract 6:

3x = 12

Divide by 3:

x = 4

We can check:

3(4 + 2)

= 3(6)

= 18

So the solution is correct.


Worked Example — Multi-Step Equation

Solve:

2(x + 5) + 3x = 25

First expand:

2x + 10 + 3x = 25

Combine like terms:

5x + 10 = 25

Subtract 10:

5x = 15

Divide by 5:

x = 3

Check:

2(3 + 5) + 3(3)

= 2(8) + 9

= 16 + 9

= 25

Therefore:

x = 3


Distribution in Geometry

The distributive property appears naturally when calculating areas.

Suppose a rectangle has:

Height = 5 cm

and:

Width = x + 3 cm

The area is:

A = 5(x + 3)

Expand:

A = 5x + 15

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Both expressions describe the same area:

5(x + 3)

and:

5x + 15


Distribution in Everyday Situations

Suppose three students each buy:

  • One notebook costing x dollars
  • One pen costing $2

The cost for one student is:

x + 2

The cost for three students is:

3(x + 2)

Using distribution:

3x + 6

This tells us that the total consists of:

3 notebooks costing 3x

and:

3 pens costing $6

Distribution can therefore help us interpret real-world situations.


A Useful Expansion Strategy

When expanding an expression:

Look at the term outside the brackets.

Then:

Multiply it by the first term.

Multiply it by the second term.

Continue until every term has been multiplied.

Then:

Remove the brackets.

Finally:

Combine like terms if possible.

For negative terms, check the signs carefully before moving on.


Checking an Expansion

Suppose you want to check:

3(x − 4) = 3x − 12

Choose:

x = 6

Left side:

3(6 − 4)

= 3(2)

= 6

Right side:

3(6) − 12

= 18 − 12

= 6

Both sides give the same result.

Substitution can therefore provide a useful check.


Common Mistakes

Mistake: Multiplying only the first term

Incorrect:

4(x + 3) = 4x + 3

Correct:

4(x + 3) = 4x + 12

The 4 must multiply every term inside the brackets.

Mistake: Forgetting the negative sign

Incorrect:

−3(x + 2) = −3x + 6

Correct:

−3(x + 2) = −3x − 6

Mistake: Mishandling two negatives

Incorrect:

−2(x − 5) = −2x − 10

Correct:

−2(x − 5) = −2x + 10

because:

Negative × Negative = Positive

Mistake: Forgetting that a lone negative sign means −1

−(x + 4)

means:

−1(x + 4)

Therefore:

−x − 4

Mistake: Stopping after expansion

Consider:

3(x + 2) + 4x

Expanding gives:

3x + 6 + 4x

but this can still be simplified:

7x + 6

Mistake: Combining unlike terms

3x + 6

cannot be simplified to:

9x

The terms are unlike.


Key Terms

Distributive property – the rule that multiplication over a grouped sum or difference can be applied to every term in the group.

Expand – remove brackets by applying multiplication to every term inside.

Bracket – a grouping symbol used to show that terms belong together.

Term – one part of an algebraic expression.

Coefficient – the numerical factor multiplying a variable.

Like terms – terms with identical variable parts.

Simplify – rewrite an expression in a simpler equivalent form.

Equivalent expressions – expressions that have the same value for every allowed value of their variables.

Factor – a quantity multiplied by another quantity.

Factoring – rewriting an expression as a product; the reverse of expansion.


Check Your Understanding

1. Expand:

3(x + 5)

2. Expand:

6(x − 2)

3. Expand:

−4(x + 3)

4. Expand:

−5(x − 2)

5. Expand:

2(3x + 4)

6. Expand:

x(x + 6)

7. Simplify:

3(x + 4) + 2x

8. Simplify:

5(x − 2) + 3x

9. Simplify:

7x − 2(x + 5)

10. Simplify:

4(x + 3) + 2(x − 1)

11. Simplify:

5(x + 2) − 3(x − 4)

12. Simplify:

10 − (2x − 3)

13. Explain the error:

4(x + 5) = 4x + 5

14. Explain why:

−3(x − 4) = −3x + 12

15. Solve:

3(x + 2) = 21

16. Solve:

2(x + 4) + 3x = 23


Key Takeaways

  • The distributive property allows us to expand brackets.
  • The term outside the brackets must multiply every term inside.
  • a(b + c) = ab + ac
  • a(b − c) = ab − ac
  • A negative value must also be distributed to every term.
  • Multiplying two negative values produces a positive value.
  • A negative sign immediately before brackets can be treated as multiplication by −1.
  • After expanding, look for like terms that can be combined.
  • Expressions can contain several sets of brackets that must each be expanded.
  • Distribution is useful when simplifying expressions and solving equations.
  • Expansion produces an expression that is equivalent to the original expression.
  • Substitution can be used to check whether an expansion is correct.
  • Distribution and factoring are reverse processes.
  • The distributive property appears in algebra, geometry, formulas, and real-world calculations.

Did You Know?

The distributive property is built into ordinary mental arithmetic. For example, you might calculate:

7 × 19

by thinking:

7(20 − 1)

Then distribute:

140 − 7 = 133

So even when people do not call it the distributive property, they often use it naturally to make calculations easier.