Inductance and Energy Storage
| サイト: | Young Education |
| コース: | Induction |
| ブック: | Inductance and Energy Storage |
| 印刷者: | Guest user |
| 日付: | 2026年 11月 9日(月曜日) 16:39 |
1. Inductance in Solenoids
Learning outcomes
- I can define inductance.
- I can explain how solenoids behave as inductors.
- I can identify factors affecting inductance.
- I can describe how coil geometry influences inductance.
- I can solve simple inductance problems.
2. Energy in Magnetic Fields
Learning outcomes
- I can explain how inductors store energy.
- I can describe magnetic field energy storage.
- I can calculate energy stored in an inductor.
- I can compare electrical and magnetic energy storage.
- I can explain practical uses of stored magnetic energy.
3. RL Circuits
Learning outcomes
- I can describe the behavior of resistor-inductor (RL) circuits.
- I can explain why current changes gradually in RL circuits.
- I can interpret current-time graphs for RL circuits.
- I can explain the concept of the RL time constant.
- I can solve simple RL circuit problems.
RL Circuits
An RL circuit is a circuit containing both a resistor (R) and an inductor (L). One of the most important features of an RL circuit is that its current cannot change instantly.
When a voltage is applied, the current rises gradually. When the voltage source is removed, the current falls gradually.
This happens because the changing current produces a changing magnetic field in the inductor. The changing magnetic flux creates a self-induced EMF that opposes the change in current.
The basic idea is:
changing current → changing magnetic field → self-induced EMF → opposition to the change in current
The Components of an RL Circuit
A simple series RL circuit contains:
- a voltage source
- a resistor
- an inductor
- connecting wires
- often a switch
The same current flows through the resistor and inductor because they are connected in series.
The resistor obeys:
V_R = IR
The inductor produces an induced voltage when current changes:
V_L = L ΔI/Δt
The inductor's induced effect opposes the change in current.
What Happens When the Switch Is Closed?
Imagine an RL circuit connected to a DC battery.
Before the switch closes:
I = 0
When the switch closes, the battery attempts to establish a current.
However, as the current begins increasing:
- the inductor's magnetic field begins increasing
- magnetic flux changes
- self-induced EMF is produced
- the induced EMF opposes the increase in current
Therefore, the current does not immediately reach its final value.
Instead:
current rises gradually
Why Current Cannot Change Instantly
The induced EMF of an inductor is related to the rate of current change:
|ε| = L|ΔI/Δt|
Imagine the current changed instantly.
Then:
Δt → 0
which would make:
ΔI/Δt
extremely large.
The corresponding induced voltage would also become extremely large.
Therefore, an ideal inductor prevents instantaneous changes in current.
An important circuit rule is:
current through an ideal inductor must change continuously.
Current Growth
When a DC voltage is first applied to a series RL circuit, current begins at zero and gradually approaches a maximum value.
The current is described by:
I = I_max(1 − e^(−t/τ))
where:
- I = current at time t
- I_max = final steady current
- t = time
- τ = RL time constant
- e ≈ 2.718
The curve rises rapidly at first and then gradually levels off.
Interpreting the Current-Growth Graph
At:
t = 0
the current is:
I = 0
Initially, the current increases rapidly.
As time passes, the rate of increase becomes smaller.
Eventually:
I → I_max
The curve approaches the final value asymptotically.
In practical calculations, the current is considered very close to its final value after several time constants.
Final Current
Once the current becomes steady:
ΔI/Δt = 0
Therefore, the self-induced EMF becomes zero.
For an ideal inductor in a DC circuit, the final current is determined by the resistance:
I_max = V/R
where:
- V = supply voltage
- R = total circuit resistance
The inductor strongly affects how quickly the current reaches this value, but an ideal inductor does not change the final steady-state current.
Example: Final Current
An RL circuit contains:
V = 12 V
R = 6.0 Ω
L = 2.0 H
Once the current becomes steady:
I_max = V/R
I_max = 12/6.0
I_max = 2.0 A
The inductance affects how quickly the current approaches 2.0 A.
The RL Time Constant
The rate at which current changes is described using the time constant.
For an RL circuit:
τ = L/R
where:
- τ = time constant in seconds (s)
- L = inductance in henries (H)
- R = resistance in ohms (Ω)
The time constant tells us approximately how quickly the circuit responds to a change.
Meaning of the Time Constant
During current growth, after one time constant:
t = τ
the current has reached approximately:
63% of its final value
Therefore:
I ≈ 0.63I_max
After two time constants:
I ≈ 0.86I_max
After three:
I ≈ 0.95I_max
After four:
I ≈ 0.98I_max
After five:
I ≈ 0.99I_max
After about 5τ, the current is normally treated as essentially steady.
Current Growth Table
| Time | Approximate Current |
|---|---|
| 0 | 0% of I_max |
| 1τ | 63% of I_max |
| 2τ | 86% of I_max |
| 3τ | 95% of I_max |
| 4τ | 98% of I_max |
| 5τ | 99% of I_max |
This pattern is useful for interpreting RL current-time graphs without performing detailed exponential calculations.
Worked Example: Finding the Time Constant
An RL circuit contains:
L = 3.0 H
R = 6.0 Ω
Use:
τ = L/R
τ = 3.0/6.0
τ = 0.50 s
After:
0.50 s
the current has reached approximately 63% of its final value.
After approximately:
5τ = 5(0.50)
5τ = 2.5 s
the current is essentially at its steady value.
Worked Example: Current After One Time Constant
An RL circuit has a final current:
I_max = 8.0 A
After one time constant:
I ≈ 0.63I_max
I ≈ (0.63)(8.0)
I ≈ 5.0 A
Effect of Inductance on the Time Constant
From:
τ = L/R
increasing inductance increases the time constant.
Therefore:
larger L → larger τ → slower current change
A larger inductor produces a greater self-induced EMF for the same rate of current change.
It therefore takes longer for the current to reach its steady value.
Effect of Resistance on the Time Constant
From:
τ = L/R
increasing resistance decreases the time constant.
Therefore:
larger R → smaller τ
However, increasing resistance also reduces the final current because:
I_max = V/R
So resistance affects both:
- the final current
- the time constant
These effects should not be confused.
Comparing Two RL Circuits
Circuit A:
L = 2.0 H
R = 4.0 Ω
Therefore:
τ_A = 2.0/4.0
τ_A = 0.50 s
Circuit B:
L = 4.0 H
R = 4.0 Ω
Therefore:
τ_B = 4.0/4.0
τ_B = 1.0 s
Circuit B has the greater inductance and therefore responds more slowly.
Current at Any Time During Growth
The full current-growth equation is:
I = I_max(1 − e^(−t/τ))
This allows the current to be calculated at any time.
Remember:
I_max = V/R
and:
τ = L/R
Worked Example: Current During Growth
An RL circuit has:
V = 12 V
R = 4.0 Ω
L = 2.0 H
Find the current after:
t = 0.50 s
First calculate the final current:
I_max = V/R
I_max = 12/4.0
I_max = 3.0 A
Now calculate the time constant:
τ = L/R
τ = 2.0/4.0
τ = 0.50 s
Therefore:
t = τ
After one time constant, the current is approximately 63% of its final value:
I ≈ 0.63(3.0)
I ≈ 1.9 A
Using the Exponential Equation
For the same circuit:
I = I_max(1 − e^(−t/τ))
I = 3.0(1 − e^(−0.50/0.50))
I = 3.0(1 − e⁻¹)
Since:
e⁻¹ ≈ 0.368
I = 3.0(1 − 0.368)
I = 3.0(0.632)
I ≈ 1.90 A
This agrees with the 63% time-constant rule.
What Happens to the Inductor Voltage?
When the circuit is first switched on, the current is changing most rapidly.
Therefore, the inductor's induced voltage is largest.
As the current approaches its steady value:
- current changes more slowly
- induced voltage decreases
Eventually:
ΔI/Δt = 0
and:
V_L = 0
for an ideal inductor under steady DC conditions.
Voltage Across the Resistor
The resistor voltage is:
V_R = IR
Immediately after switching on:
I = 0
so:
V_R = 0
As current increases:
V_R increases
Eventually:
I = V/R
so:
V_R = V
for the ideal series RL circuit.
Voltage Changes During Current Growth
The behaviour can be summarized:
| Time | Current | Resistor Voltage | Inductor Voltage |
|---|---|---|---|
| Immediately after switch closes | 0 | 0 | Maximum |
| During growth | Increasing | Increasing | Decreasing |
| Long after switch closes | Maximum and steady | Supply voltage | 0 |
This demonstrates how the inductor initially opposes the establishment of current.
Kirchhoff's Voltage Law in an RL Circuit
At any moment during current growth:
V = V_R + V_L
Therefore:
V = IR + L ΔI/Δt
The supply voltage is shared between the resistor and the inductor.
Initially, most of the voltage appears across the inductor.
Later, as current becomes steady, most or all of the supply voltage appears across the resistor in the ideal model.
Energy During Current Growth
While current increases, the inductor stores energy in its magnetic field.
The stored energy is:
E = ½LI²
As current increases:
- magnetic field strengthens
- stored magnetic energy increases
At the final steady current:
E_max = ½LI_max²
Worked Example: Final Stored Energy
An RL circuit contains:
L = 2.0 H
V = 12 V
R = 6.0 Ω
Final current:
I_max = V/R
I_max = 12/6.0
I_max = 2.0 A
Stored energy:
E = ½LI²
E = ½(2.0)(2.0²)
E = 4.0 J
Switching the Circuit Off
Suppose an inductor is carrying a steady current and the supply is removed while a closed path remains available for the current.
The current attempts to decrease.
The magnetic field begins collapsing.
This produces a self-induced EMF that acts to maintain the original current.
Therefore:
the current decreases gradually rather than instantly
This process is called current decay.
Current Decay
For a simple RL decay circuit:
I = I₀e^(−t/τ)
where:
- I = current at time t
- I₀ = initial current
- τ = L/R
- t = time
The current decreases exponentially.
It approaches zero but does not mathematically reach exactly zero in the ideal exponential model.
Interpreting the Current-Decay Graph
At:
t = 0
the current is:
I = I₀
After one time constant:
I ≈ 0.37I₀
After two:
I ≈ 0.14I₀
After three:
I ≈ 0.050I₀
After four:
I ≈ 0.018I₀
After five:
I ≈ 0.007I₀
So after approximately five time constants, the current is usually treated as essentially zero.
Current Decay Table
| Time | Current Remaining |
|---|---|
| 0 | 100% |
| 1τ | 37% |
| 2τ | 14% |
| 3τ | 5% |
| 4τ | 2% |
| 5τ | Less than 1% |
Notice the connection:
During growth after one τ:
63% reached
During decay after one τ:
37% remains
because:
63% + 37% = 100%
approximately.
Worked Example: Current Decay
An inductor initially carries:
I₀ = 6.0 A
The circuit has:
L = 2.0 H
R = 4.0 Ω
Calculate the time constant:
τ = L/R
τ = 2.0/4.0
τ = 0.50 s
After one time constant:
I ≈ 0.37I₀
I ≈ 0.37(6.0)
I ≈ 2.2 A
Current After Two Time Constants
Using the same circuit:
t = 2τ
Approximately 14% of the original current remains.
I ≈ 0.14(6.0)
I ≈ 0.84 A
Using the exponential equation gives approximately the same result.
Growth vs Decay Graphs
The two graphs have different shapes.
Current growth:
- begins at zero
- rises rapidly at first
- gradually levels off
- approaches I_max
Current decay:
- begins at I₀
- falls rapidly at first
- gradually levels off
- approaches zero
Both are exponential curves.
Reading the Time Constant from a Graph
For a current-growth graph:
- identify the final current I_max
- calculate 63% of I_max
- find where the curve reaches this value
- read the corresponding time
That time is approximately:
τ
For a current-decay graph:
- identify the initial current I₀
- calculate 37% of I₀
- find where the curve reaches this value
- read the corresponding time
That time is approximately:
τ
Example: Finding τ from a Growth Graph
Suppose a graph approaches a final current of:
10 A
Calculate 63%:
0.63(10)
6.3 A
If the graph reaches 6.3 A at:
0.40 s
then:
τ = 0.40 s
If R = 5.0 Ω, then:
τ = L/R
so:
L = τR
L = (0.40)(5.0)
L = 2.0 H
Example: Finding τ from a Decay Graph
Suppose current begins at:
8.0 A
After one time constant, the current should be:
0.37(8.0)
≈ 3.0 A
If the graph reaches approximately 3.0 A at:
0.25 s
then:
τ ≈ 0.25 s
Comparing Different Time Constants
A circuit with a small time constant changes current quickly.
Its current-time graph is relatively steep.
A circuit with a large time constant changes current more slowly.
Its graph is more gradual.
Therefore:
larger τ → slower response
smaller τ → faster response
Effect of Increasing Inductance on the Graph
If resistance remains constant and inductance increases:
τ = L/R
so τ increases.
The current-growth graph becomes more gradual.
The circuit takes longer to approach its final current.
Similarly, during decay, the current remains significant for a longer time.
Effect of Increasing Resistance on the Graph
If inductance remains constant and resistance increases:
τ = L/R
so τ decreases.
The current responds more quickly.
However, during current growth from a fixed-voltage supply:
I_max = V/R
also decreases.
Therefore, increasing resistance changes both:
- the time scale
- the final current
This is an important point when comparing graphs.
Complete Growth Problem
A series RL circuit contains:
V = 24 V
R = 8.0 Ω
L = 4.0 H
Find the final current, time constant, and current after one time constant.
Final current:
I_max = V/R
I_max = 24/8.0
I_max = 3.0 A
Time constant:
τ = L/R
τ = 4.0/8.0
τ = 0.50 s
After one time constant:
I ≈ 0.63I_max
I ≈ 0.63(3.0)
I ≈ 1.9 A
After about:
5τ = 2.5 s
the current is essentially at its final value.
Complete Decay Problem
An RL circuit initially carries:
I₀ = 5.0 A
The circuit has:
L = 1.5 H
R = 3.0 Ω
Time constant:
τ = L/R
τ = 1.5/3.0
τ = 0.50 s
Find the current after:
t = 1.0 s
Since:
1.0 s = 2τ
approximately 14% remains:
I ≈ 0.14(5.0)
I ≈ 0.70 A
Using the exact equation:
I = I₀e^(−t/τ)
I = 5.0e^(−1.0/0.50)
I = 5.0e⁻²
I ≈ 5.0(0.135)
I ≈ 0.68 A
Finding Time Using the Exponential Equation
Sometimes the unknown is time.
For decay:
I = I₀e^(−t/τ)
Suppose the current falls to half its initial value:
I/I₀ = 0.50
Then:
0.50 = e^(−t/τ)
Taking the natural logarithm:
ln(0.50) = −t/τ
Therefore:
t = −τ ln(0.50)
Since:
ln(0.50) ≈ −0.693
then:
t ≈ 0.693τ
So an RL decay does not take one full time constant to fall to half its initial current.
Energy During Current Decay
As current decreases, the magnetic energy:
E = ½LI²
also decreases.
The collapsing magnetic field transfers energy back into the circuit.
In a simple resistor-inductor decay circuit, much of this energy eventually becomes thermal energy in the resistor.
Therefore:
magnetic field energy → electrical energy → thermal energy
Why Switching an Inductor Can Produce a Large Voltage
If the circuit is opened suddenly without a suitable current path, the current attempts to fall very rapidly.
From:
|ε| = L|ΔI/Δt|
a very large rate of change of current can produce a very large induced voltage.
This can cause:
- sparks across switches
- damage to electronic components
- electrical interference
Practical circuits often provide a safe path for the current to decay.
Flyback Protection
Coils in relays, motors, and solenoids can behave as inductive loads.
When they are switched off, their stored magnetic energy must be released.
A protective component such as a flyback diode can provide a temporary current path.
The current then decreases gradually instead of producing a damaging voltage spike.
Practical Uses of RL Behavior
RL circuits appear wherever coils and changing currents are present.
Examples include:
- electromagnets
- relays
- solenoids
- electric motors
- transformers
- power supplies
- electronic filters
- switching circuits
In each case, inductance affects how rapidly current can change.
RL Circuits in Electromagnets
An electromagnet contains a coil with inductance.
When switched on:
- current gradually increases
- magnetic field gradually strengthens
When switched off:
- current gradually decreases if a path remains
- magnetic field collapses
- stored energy is released
The time constant therefore influences how quickly the electromagnet responds.
RL Circuits in Motors
Motor windings have both:
- resistance
- inductance
They therefore behave partly like RL circuits.
The inductance prevents motor current from changing instantly.
This affects:
- starting behaviour
- current control
- switching
- motor speed control
- electronic drive design
RL Circuits and Filters
Inductors oppose rapid current changes.
This makes them useful in electrical filters.
Rapidly changing signals can experience stronger inductive effects than slowly changing signals.
RL networks can therefore help:
- reduce electrical noise
- separate signals by frequency
- smooth current
- shape electrical signals
RL Circuits vs Purely Resistive Circuits
A purely resistive DC circuit responds almost immediately in the ideal model.
Its current is:
I = V/R
An RL circuit behaves differently during switching because the inductor produces self-induced EMF.
| Pure Resistor Circuit | RL Circuit |
|---|---|
| No significant inductance | Contains inductance |
| Current changes essentially immediately in ideal model | Current changes gradually |
| No magnetic energy storage | Stores magnetic energy |
| I determined by V/R | Final I determined by V/R |
| No RL time constant | τ = L/R |
RL Circuits and RC Circuits
RL and RC circuits both show exponential behaviour, but they involve different quantities.
| RL Circuit | RC Circuit |
|---|---|
| Resistor + inductor | Resistor + capacitor |
| Current changes gradually | Capacitor voltage changes gradually |
| Stores magnetic energy | Stores electric-field energy |
| τ = L/R | τ = RC |
| Inductor opposes current change | Capacitor opposes voltage change |
Both systems are important examples of circuits with time-dependent behaviour.
A Reliable Strategy for RL Problems
First identify:
- V = supply voltage
- R = resistance
- L = inductance
- t = time
Calculate the time constant:
τ = L/R
For current growth, calculate the final current:
I_max = V/R
Then use either the approximate time-constant percentages or:
I = I_max(1 − e^(−t/τ))
For current decay use:
I = I₀e^(−t/τ)
Remember:
growth at 1τ → 63%
decay at 1τ → 37% remaining
After approximately:
5τ
the change is essentially complete.
Common Mistakes
Thinking current changes instantly in an RL circuit
Inductance opposes changes in current.
Thinking the inductor stops current permanently
The inductor mainly affects changing current. With steady DC, an ideal inductor has zero induced voltage.
Using τ = R/L
For an RL circuit:
τ = L/R
Confusing 63% and 37%
During growth after one τ:
63% of final current has been reached.
During decay after one τ:
37% of initial current remains.
Thinking the time constant is the time required to complete the change
The exponential process is not mathematically complete after one τ. One τ describes a characteristic fraction of the change.
Forgetting to calculate the final current
For a simple DC series RL circuit:
I_max = V/R
Using the growth equation for decay
Growth:
I = I_max(1 − e^(−t/τ))
Decay:
I = I₀e^(−t/τ)
Thinking resistance only affects the time constant
Resistance also affects the final current.
Ignoring stored magnetic energy
During current decay, the magnetic field releases energy back into the circuit.
Key Terms
RL circuit — circuit containing resistance and inductance.
Resistor — component that opposes current and dissipates electrical energy, commonly as thermal energy.
Inductor — component that stores energy in a magnetic field and opposes changes in current.
Inductance — measure of an inductor's ability to produce self-induced EMF.
Self-induction — production of an EMF caused by a circuit's own changing current.
Self-induced EMF — induced voltage produced when a circuit's own magnetic flux changes.
Steady state — condition in which current has stopped changing with time.
Transient — temporary period during which current or voltage changes from one steady condition toward another.
Time constant — characteristic time describing how quickly an RL circuit responds.
Current growth — exponential increase of current toward its final value after a DC source is applied.
Current decay — exponential decrease of current after the source is removed while a suitable current path remains.
Exponential change — change whose rate depends on how far the system remains from its final state.
Magnetic energy — energy stored in the magnetic field of an inductor.
Flyback diode — protective component providing a current path for an inductive load when it is switched off.
Key Takeaways
- An RL circuit contains both resistance and inductance.
- Current cannot change instantly through an ideal inductor.
- Self-induction causes the inductor to oppose changes in current.
- When a DC source is connected, current rises gradually toward its final value.
- The final current in a simple ideal series RL circuit is I_max = V/R.
- The RL time constant is τ = L/R.
- Larger inductance produces a larger time constant and slower current response.
- Larger resistance produces a smaller time constant when inductance remains fixed.
- After one time constant during growth, current reaches about 63% of its final value.
- After one time constant during decay, about 37% of the original current remains.
- After approximately five time constants, the transition is normally considered essentially complete.
- Current growth follows I = I_max(1 − e^(−t/τ)).
- Current decay follows I = I₀e^(−t/τ).
- Current-time graphs for RL circuits are exponential rather than straight lines.
- During switch-on, inductor voltage is initially large and decreases toward zero.
- During switch-on, resistor voltage increases as current increases.
- Inductors store energy according to E = ½LI².
- During current decay, stored magnetic energy is transferred back into the circuit.
- Rapidly interrupting an inductive current can produce a large voltage.
- RL behaviour is important in motors, relays, electromagnets, power supplies, filters, and switching circuits.
Check Your Understanding
- What is an RL circuit?
- Explain why current cannot change instantly through an ideal inductor.
- Describe what happens to the current immediately after a DC source is connected to an RL circuit.
- A circuit contains L = 4.0 H and R = 8.0 Ω. Calculate its time constant.
- Explain what a time constant of 0.50 s means during current growth.
- An RL circuit has a final current of 10 A. Approximately what current flows after one time constant?
- A current begins at 8.0 A and decays through an RL circuit. Approximately what current remains after one time constant?
- A 12 V supply is connected to a series RL circuit containing R = 3.0 Ω and L = 1.5 H. Calculate the final current and time constant.
- For the circuit in Question 8, estimate the current after one time constant.
- An RL circuit has I_max = 6.0 A and τ = 0.40 s. Calculate the current after 0.80 s using I = I_max(1 − e^(−t/τ)).
- An inductor initially carries 5.0 A in a circuit with τ = 0.25 s. Calculate the current remaining after 0.50 s.
- Describe the shape of a current-time graph when an RL circuit is switched on. How would increasing inductance change the graph?
- Explain how the voltage across the resistor and the voltage across the inductor change from the moment a DC RL circuit is switched on until steady state is reached.
- Explain where the energy stored in an inductor goes when the current through an RL circuit decreases.
- Two RL circuits have the same resistance, but Circuit A has twice the inductance of Circuit B. Compare their time constants and explain which circuit's current changes more slowly.
4. Mutual Inductance
Learning outcomes
- I can define mutual inductance.
- I can explain how energy is transferred between coils.
- I can identify factors affecting mutual inductance.
- I can compare mutual inductance with self-inductance.
- I can explain how mutual inductance is used in electrical devices.
Mutual Inductance
Mutual inductance describes the ability of a changing current in one circuit to produce an induced EMF in another nearby circuit.
When current in the first coil changes, its magnetic field changes. If some of this changing magnetic field passes through a second coil, the magnetic flux through the second coil changes. According to Faraday's law, this changing flux produces an induced EMF.
The process can be summarized as:
changing current in Coil 1 → changing magnetic field → changing flux through Coil 2 → induced EMF in Coil 2
Mutual inductance allows electrical energy and signals to be transferred between circuits without requiring a direct electrical connection.
Defining Mutual Inductance
The strength of the electromagnetic interaction between two circuits is measured by their mutual inductance.
The symbol is:
M
The SI unit is the:
henry (H)
For two coils, the magnitude of the induced EMF in Coil 2 can be written:
|ε₂| = M|ΔI₁/Δt|
where:
- ε₂ = induced EMF in Coil 2
- M = mutual inductance
- ΔI₁ = change in current in Coil 1
- Δt = time interval
Including direction:
ε₂ = −M ΔI₁/Δt
The negative sign represents Lenz's law.
Meaning of Mutual Inductance
A large value of M means the coils are strongly coupled.
A relatively small change in primary current can produce a significant induced EMF in the second coil.
A small value of M means the coils are weakly coupled.
For the same rate of current change:
larger M → larger induced EMF
Meaning of One Henry
Suppose two coils have:
M = 1 H
If current in the first coil changes at:
1 A/s
the magnitude of the induced EMF in the second coil is:
1 V
Therefore:
1 H = 1 V·s/A
The henry is used for both:
- self-inductance
- mutual inductance
How Mutual Induction Occurs
Consider two nearby coils.
Coil 1 carries a changing current.
This changing current produces a changing magnetic field.
Some of that field passes through Coil 2.
Therefore, the magnetic flux through Coil 2 changes.
Faraday's law states:
ε = −N ΔΦ/Δt
so an EMF appears in Coil 2.
If Coil 2 forms part of a closed circuit, this EMF can produce a current.
EMF Does Not Always Mean Current
An important distinction is:
changing magnetic flux produces an EMF
but current flows only if there is a complete conducting path.
Therefore, an open secondary coil can have an induced voltage across its terminals even though no current flows.
If the secondary circuit is closed:
induced EMF → induced current
Energy Transfer Between Coils
Mutual inductance allows energy to move from one circuit to another through a magnetic field.
The basic energy pathway is:
electrical energy in Coil 1 → changing magnetic field → electrical energy in Coil 2
The coils do not need to touch.
They also do not need a direct electrical connection.
Instead, they must be magnetically coupled.
Primary and Secondary Coils
In many mutual-induction systems, the coils are called:
Primary coil — receives the original electrical input.
Secondary coil — receives energy through electromagnetic induction.
The changing current in the primary creates the changing magnetic flux responsible for the induced EMF in the secondary.
These terms are especially common when discussing transformers.
Energy Is Conserved
Mutual inductance does not create energy.
Energy transferred to the secondary ultimately comes from the source connected to the primary.
For an ideal system:
input energy = output energy
and:
input power = output power
Real devices lose some energy through:
- electrical resistance
- eddy currents
- magnetic hysteresis
- flux leakage
- heating
Therefore:
P_output < P_input
in real systems.
Why Changing Current Is Required
Suppose the primary carries a constant current.
A constant current produces a constant magnetic field.
A constant magnetic field produces constant magnetic flux through the secondary.
Therefore:
ΔΦ/Δt = 0
and:
ε₂ = 0
So a steady current does not produce continuous mutual induction.
What matters is:
changing current
rather than simply the presence of current.
Switching DC On and Off
A DC circuit can still produce mutual induction briefly.
When the primary is switched on:
- current increases
- magnetic field increases
- secondary flux increases
- EMF is induced
Once the current becomes steady:
induced EMF → 0
When the primary is switched off:
- current decreases
- magnetic field collapses
- secondary flux decreases
- another EMF is induced
The induced EMF during switch-off has the opposite direction from that during switch-on.
Alternating Current
Alternating current continually changes.
Therefore:
AC → changing magnetic field → changing magnetic flux → continuous induced EMF
This makes AC especially useful for devices based on mutual induction.
Transformers are the most important example.
Factors Affecting Mutual Inductance
Mutual inductance depends on how effectively the magnetic field from one coil links with the other.
Important factors include:
- number of turns
- distance between coils
- orientation of coils
- amount of overlap
- coil size and geometry
- magnetic core
- magnetic permeability
- leakage flux
Together, these determine the strength of magnetic coupling.
Number of Turns
Increasing the number of turns can increase mutual inductance.
More turns in the primary can strengthen its magnetic effect.
More turns in the secondary provide greater total flux linkage.
Therefore:
more turns → potentially greater mutual inductance
The exact relationship depends on the geometry of the two coils.
Distance Between the Coils
Mutual inductance generally becomes smaller as the coils are moved farther apart.
At greater distances:
- less primary magnetic field reaches the secondary
- less flux links the secondary
- coupling becomes weaker
Therefore:
greater separation → smaller M
in typical arrangements.
Coil Orientation
The relative orientation of the coils is extremely important.
If the coils are aligned so that much of the primary field passes through the secondary:
mutual inductance is relatively large
If one coil is rotated:
- less magnetic flux may pass through it
- flux linkage decreases
- mutual inductance decreases
Why Orientation Matters
Magnetic flux is:
Φ = BA cos θ
where θ is the angle between the magnetic field and the normal to the coil.
When the magnetic field is perpendicular to the plane of the coil:
θ = 0°
and:
Φ = BA
The flux is maximum.
If the field lies parallel to the plane:
θ = 90°
and:
Φ = 0
Therefore, changing the orientation of the secondary can dramatically change the magnetic flux linking it.
Coil Overlap
Coils that strongly overlap can share more magnetic flux.
If the coils are moved sideways so that their overlap decreases, less magnetic flux may link them.
Therefore:
greater effective overlap → stronger coupling
This principle is important in wireless power-transfer systems.
Magnetic Cores
A suitable magnetic core can greatly increase mutual inductance.
The core provides a path that guides magnetic flux from one coil through the other.
This can:
- increase magnetic flux
- reduce leakage
- improve coupling
- increase mutual inductance
- improve energy transfer
Transformer cores are designed for exactly this purpose.
Flux Leakage
Not all magnetic flux produced by the primary necessarily passes through the secondary.
The portion that does not link effectively with the other coil is called leakage flux.
Greater leakage means:
- weaker magnetic coupling
- smaller mutual inductance
- less effective energy transfer
Reducing leakage is therefore important when strong coupling is required.
Coupling Coefficient
The degree of magnetic coupling can also be described by the coupling coefficient, k.
For two coils:
M = k√(L₁L₂)
where:
- M = mutual inductance
- L₁ = self-inductance of Coil 1
- L₂ = self-inductance of Coil 2
- k = coupling coefficient
For idealized systems:
0 ≤ k ≤ 1
Meaning of the Coupling Coefficient
If:
k ≈ 1
the coils are very strongly coupled.
If:
k ≈ 0
the coils are very weakly coupled.
The equation:
M = k√(L₁L₂)
shows that mutual inductance depends on both:
- the inductances of the individual coils
- how effectively they are magnetically coupled
Worked Example: Coupling Coefficient
Two coils have:
L₁ = 4.0 H
L₂ = 9.0 H
and:
k = 0.50
Use:
M = k√(L₁L₂)
M = 0.50√[(4.0)(9.0)]
M = 0.50√36
M = 0.50(6.0)
M = 3.0 H
Worked Example: Induced EMF
Two coils have mutual inductance:
M = 0.40 H
The current in Coil 1 changes from:
2.0 A to 8.0 A
in:
0.30 s
Calculate:
ΔI₁ = 8.0 − 2.0
ΔI₁ = 6.0 A
Rate of current change:
ΔI₁/Δt = 6.0/0.30
ΔI₁/Δt = 20 A/s
Then:
|ε₂| = M|ΔI₁/Δt|
|ε₂| = (0.40)(20)
|ε₂| = 8.0 V
Worked Example: Finding Mutual Inductance
A changing current in Coil 1 produces an induced EMF of:
12 V
in Coil 2.
The current changes at:
30 A/s
Use:
|ε₂| = M|ΔI₁/Δt|
Rearrange:
M = |ε₂| / |ΔI₁/Δt|
M = 12/30
M = 0.40 H
Worked Example: Finding Rate of Current Change
Two coils have:
M = 0.25 H
The secondary experiences:
|ε₂| = 5.0 V
Use:
|ΔI₁/Δt| = |ε₂|/M
|ΔI₁/Δt| = 5.0/0.25
|ΔI₁/Δt| = 20 A/s
Self-Inductance
Self-inductance occurs when a changing current produces an induced EMF in the same circuit.
The relationship is:
ε = −L ΔI/Δt
where L is the self-inductance.
The coil responds to changes in its own current.
Mutual Inductance
Mutual inductance occurs when changing current in one circuit induces an EMF in another circuit.
The relationship is:
ε₂ = −M ΔI₁/Δt
where M is the mutual inductance.
The second coil responds to the changing magnetic field produced by the first.
Comparing Self-Inductance and Mutual Inductance
| Self-Inductance | Mutual Inductance |
|---|---|
| Occurs within the same circuit | Occurs between two circuits |
| Uses L | Uses M |
| ε = −L ΔI/Δt | ε₂ = −M ΔI₁/Δt |
| Circuit responds to its own changing current | Second circuit responds to changing current in first |
| Important in inductors and RL circuits | Important in transformers and coupled coils |
| Measured in henries | Measured in henries |
Both are consequences of Faraday's law and Lenz's law.
Both Effects Can Occur Together
Suppose two coils are placed around the same magnetic core.
When current changes in Coil 1:
- Coil 1 experiences self-induction
- Coil 2 experiences mutual induction
Therefore, self-inductance and mutual inductance can occur simultaneously.
This happens in transformers.
Transformers
A transformer is one of the most important applications of mutual inductance.
It contains:
- a primary winding
- a secondary winding
- usually a magnetic core
Alternating current in the primary produces a continuously changing magnetic field.
The core guides much of this changing magnetic flux through the secondary.
An alternating EMF is then induced in the secondary.
Energy Transfer in a Transformer
The transformer energy pathway can be represented as:
electrical energy in primary
↓
changing magnetic field
↓
changing magnetic flux through secondary
↓
electrical energy in secondary
The windings can remain electrically isolated even though energy is transferred between them.
Transformer Voltage Ratio
For an ideal transformer:
V_s/V_p = N_s/N_p
where:
- V_s = secondary voltage
- V_p = primary voltage
- N_s = number of secondary turns
- N_p = number of primary turns
Changing the turns ratio allows the transformer to change voltage.
Step-Up Transformers
For a step-up transformer:
N_s > N_p
so:
V_s > V_p
The transformer increases voltage.
For an ideal transformer, this increase in voltage is accompanied by a decrease in current.
Step-Down Transformers
For a step-down transformer:
N_s < N_p
so:
V_s < V_p
The transformer decreases voltage.
For an ideal transformer, the secondary current can then be greater than the primary current.
Wireless Charging
Wireless charging is another important application of mutual inductance.
A transmitter coil carries alternating current.
This creates a changing magnetic field.
A receiver coil inside the device experiences changing magnetic flux.
An EMF is induced in the receiver.
The resulting electrical energy can be used to charge a battery.
Why Wireless Charger Position Matters
If the transmitter and receiver coils are well aligned:
- magnetic coupling is stronger
- mutual inductance is greater
- more flux links the receiver
If the device is badly aligned:
- coupling becomes weaker
- less flux links the receiver
- energy transfer becomes less effective
This is why the position of a device on a wireless charging pad matters.
Electric Toothbrush Charging
Inductive charging is useful in devices where exposed electrical contacts may be undesirable.
Some electric toothbrush chargers contain:
- a transmitting coil in the base
- a receiving coil in the toothbrush
Changing current in the base produces a changing magnetic field.
Mutual induction transfers energy to the toothbrush without requiring exposed electrical contacts between the charger and device.
Inductive Sensors
Mutual inductance is also used in sensing systems.
A changing magnetic field produced by one coil can interact with:
- another coil
- conducting objects
- magnetic materials
Changes in coupling can then be detected electrically.
Applications include:
- position sensors
- proximity sensors
- metal detectors
- industrial measurement systems
Signal Transfer
Mutual inductance can transfer changing electrical signals between circuits.
Small transformers are used in some electronic systems for:
- signal coupling
- electrical isolation
- impedance matching
- noise control
The circuits can exchange energy and information without sharing a direct conductive path.
Ignition Systems
Some ignition systems use strongly coupled coils.
Energy is first stored in a magnetic field.
When current changes rapidly, a large change in magnetic flux occurs.
A secondary winding with many turns can develop a very large voltage.
This high voltage can then be used to create an electrical spark.
Electrical Isolation
Transformers can provide galvanic isolation.
The primary and secondary may have no direct conducting connection.
Instead:
energy crosses through magnetic coupling
This can help:
- improve safety
- isolate sensitive circuits
- reduce unwanted ground connections
- protect equipment
Strong and Weak Coupling
Consider two identical pairs of coils.
System A
The coils are:
- close together
- aligned
- wrapped around the same magnetic core
This system has relatively strong coupling and high mutual inductance.
System B
The coils are:
- far apart
- poorly aligned
- surrounded mainly by air
This system has much weaker coupling and lower mutual inductance.
Comparing Coil Arrangements
Suppose the same changing primary current is applied to several arrangements.
The largest induced secondary voltage would generally occur when the coils have:
- many turns
- close spacing
- strong alignment
- large useful overlap
- a suitable shared magnetic core
The smallest induced voltage would generally occur when the coils are:
- far apart
- poorly aligned
- weakly coupled
Energy Transfer Efficiency
Strong mutual inductance does not automatically mean a device is perfectly efficient.
Real systems can lose energy because of:
- wire resistance
- eddy-current heating
- hysteresis
- leakage flux
- electromagnetic radiation
- other circuit losses
Designers therefore try to achieve strong useful coupling while minimizing losses.
Mutual Inductance and Eddy Currents
Mutual induction involves intended coupling between circuits or coils.
However, changing magnetic fields can also induce unwanted circulating currents in nearby conducting materials.
These are eddy currents.
For example, transformer cores can develop eddy currents.
Laminated cores help reduce these unwanted currents and their associated heating.
Mutual Inductance and RL Circuits
The primary winding of a transformer has self-inductance.
Therefore, its current does not necessarily change instantaneously.
At the same time, its changing magnetic field can induce an EMF in another winding.
So the concepts studied in:
- self-induction
- inductance
- RL circuits
- magnetic energy
- mutual induction
are closely connected.
A Complete Calculation
Two coils have:
M = 0.60 H
The primary current decreases from:
8.0 A to 2.0 A
in:
0.20 s
Change in current:
ΔI₁ = 2.0 − 8.0
ΔI₁ = −6.0 A
Magnitude of the rate:
|ΔI₁/Δt| = 6.0/0.20
|ΔI₁/Δt| = 30 A/s
Induced EMF:
|ε₂| = M|ΔI₁/Δt|
|ε₂| = (0.60)(30)
|ε₂| = 18 V
The induced effect acts according to Lenz's law to oppose the decrease in magnetic flux.
Complete Coupling Problem
Two coils have:
L₁ = 0.80 H
L₂ = 0.20 H
and coupling coefficient:
k = 0.75
Calculate their mutual inductance.
Use:
M = k√(L₁L₂)
M = 0.75√[(0.80)(0.20)]
M = 0.75√0.16
M = 0.75(0.40)
M = 0.30 H
If current in Coil 1 changes at:
10 A/s
then:
|ε₂| = M|ΔI₁/Δt|
|ε₂| = (0.30)(10)
|ε₂| = 3.0 V
A Reliable Strategy for Mutual-Inductance Problems
First identify:
- which coil has the changing current
- which coil experiences the induced EMF
- whether the coils are magnetically coupled
For a simple induced-EMF problem use:
|ε₂| = M|ΔI₁/Δt|
For coupling problems use:
M = k√(L₁L₂)
For transformer problems, the turns ratio may be needed:
V_s/V_p = N_s/N_p
Then consider the physical arrangement:
- distance
- orientation
- turns
- core material
- overlap
- leakage flux
Finally, use Lenz's law if the direction of the induced effect is required.
Common Mistakes
Confusing mutual inductance with mutual induction
Mutual induction is the process. Mutual inductance M is the quantity describing the strength of coupling.
Thinking the coils must be electrically connected
They can transfer energy magnetically while remaining electrically isolated.
Thinking a steady current continuously induces an EMF
A steady current produces a steady field. Continuous induction requires changing magnetic flux.
Ignoring coil position
Distance and orientation strongly affect coupling.
Assuming all magnetic flux links both coils
Some flux can leak away.
Confusing L and M
L describes self-inductance. M describes mutual inductance.
Forgetting the rate of current change
Induced EMF depends on ΔI/Δt, not simply the amount of current.
Assuming energy is created in the secondary
Energy transferred to the secondary ultimately comes from the primary circuit.
Thinking stronger coupling means perfect efficiency
Resistance, core losses, leakage, and other effects can still reduce efficiency.
Key Terms
Mutual inductance — measure of how strongly changing current in one circuit induces an EMF in another circuit.
Mutual induction — process by which changing current in one circuit produces an induced EMF in another.
Self-inductance — ability of a circuit's changing current to induce an EMF in the same circuit.
Henry (H) — SI unit of self-inductance and mutual inductance.
Primary coil — coil carrying the changing current that produces the changing magnetic field.
Secondary coil — coil in which an EMF is induced by changing magnetic flux from another coil.
Magnetic coupling — degree to which magnetic flux produced by one circuit links another circuit.
Coupling coefficient — number k describing the strength of magnetic coupling between two inductors.
Flux linkage — total magnetic flux linked with the turns of a coil.
Leakage flux — magnetic flux that does not effectively link both coupled coils.
Faraday's law — relationship between changing magnetic flux and induced EMF.
Lenz's law — principle stating that an induced effect opposes the change producing it.
Transformer — device that transfers electrical energy between circuits using mutual induction.
Galvanic isolation — separation of circuits so there is no direct conductive connection between them.
Wireless power transfer — transfer of electrical energy without direct electrical contacts, often using magnetic coupling.
Key Takeaways
- Mutual inductance describes electromagnetic coupling between two circuits.
- Its symbol is M and its SI unit is the henry.
- Changing current in one coil produces a changing magnetic field.
- Changing magnetic flux through another coil produces an induced EMF.
- For simple situations, |ε₂| = M|ΔI₁/Δt|.
- Faster current changes produce larger induced EMFs.
- Greater mutual inductance produces larger induced EMFs for the same rate of current change.
- Mutual induction transfers energy through magnetic fields rather than through a direct electrical connection.
- A secondary circuit must be closed for an induced current to flow, although an induced EMF can exist in an open circuit.
- Mutual inductance depends on coil geometry, turns, distance, orientation, overlap, and core material.
- Moving coils closer together generally increases coupling.
- Better coil alignment generally increases coupling.
- A suitable common magnetic core can greatly increase mutual inductance.
- Leakage flux reduces magnetic coupling.
- The coupling coefficient can be used with M = k√(L₁L₂).
- Self-inductance involves one circuit responding to its own changing current.
- Mutual inductance involves one circuit responding to changing current in another circuit.
- Both self-inductance and mutual inductance follow Faraday's and Lenz's laws.
- Transformers use mutual inductance to transfer electrical energy between windings.
- Wireless chargers use magnetic coupling between transmitter and receiver coils.
- Mutual inductance is also important in sensors, ignition systems, signal transformers, and electrically isolated circuits.
Check Your Understanding
- Define mutual inductance and state its SI unit.
- Explain the difference between mutual induction and mutual inductance.
- Describe how changing current in one coil can produce an EMF in another coil.
- Why does a constant DC current in the primary not continuously induce an EMF in the secondary?
- Explain how energy can be transferred between two coils that have no direct electrical connection.
- Identify four factors that can affect mutual inductance between two coils.
- Explain why moving two coils farther apart generally decreases their mutual inductance.
- Explain why changing the orientation of one coil can affect the induced EMF.
- Two coils have M = 0.30 H. Current in Coil 1 changes at 20 A/s. Calculate the magnitude of the induced EMF in Coil 2.
- A secondary coil experiences an induced EMF of 12 V when primary current changes at 40 A/s. Calculate the mutual inductance.
- Two coils have L₁ = 2.0 H, L₂ = 8.0 H, and k = 0.50. Calculate their mutual inductance.
- Compare self-inductance and mutual inductance. Give at least two similarities and two differences.
- Explain how mutual inductance allows a transformer to transfer electrical energy from its primary winding to its secondary winding.
- Explain why correct alignment between transmitter and receiver coils is important in a wireless charging system.
- An engineer wants to increase the mutual inductance between two coils. Describe at least four changes that could be made to their design or arrangement and explain why each would help.
5. Practical Inductance Applications
Learning outcomes
- I can identify devices that use inductors.
- I can explain the role of inductors in electrical circuits.
- I can describe how inductors reduce electrical noise.
- I can explain how inductors are used in power supplies.
- I can evaluate the advantages of inductors in modern electronics.