Resistance and DC Circuits
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| Книга: | Resistance and DC Circuits |
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| Дата: | понеділок 9 листопада 2026 16:40 PM |
1. Resistance
Learning outcomes
- I can define electrical resistance.
- I can identify factors affecting resistance.
- I can describe resistivity.
- I can compare conductors and resistors.
- I can explain resistance microscopically.
2. Ohm's Law
Learning outcomes
- I can state Ohm's Law.
- I can calculate voltage, current, and resistance.
- I can identify ohmic conductors.
- I can interpret V-I graphs.
- I can solve circuit problems using Ohm's Law.
3. Series Circuits
Learning outcomes
- I can describe current and voltage in series circuits.
- I can calculate equivalent resistance.
- I can predict the effect of adding components.
- I can analyze simple series circuits.
- I can compare experimental and theoretical results.
Series Circuits
What Is a Series Circuit?
A series circuit is a circuit in which components are connected one after another in a single continuous path.
Because there is only one path for charge to follow, the same current passes through every component in the circuit.
A simple series circuit might contain:
- a battery or power supply
- a switch
- two or more resistors or lamps
- connecting wires
The main rules for a series circuit are:
Current is the same everywhere.
Voltages across components add to the supply voltage.
Resistances add together.
These three rules allow us to analyze most simple series circuits.
Current in a Series Circuit
Because a series circuit has only one path, charge cannot split into different branches.
Therefore:
I_total = I₁ = I₂ = I₃ = ...
If the current leaving the battery is:
2 A
then the current through every component in the series circuit is also:
2 A
The current is not used up as it moves around the circuit.
Why Is Current the Same?
Current is the rate of flow of charge:
I = Q/t
where:
- I = current
- Q = charge
- t = time
Suppose 10 C of charge passes one point in the circuit during a certain time.
The same 10 C must pass the next component.
Charge does not normally accumulate inside a resistor or lamp.
Therefore, the rate of charge flow must be the same throughout a steady series circuit.
Measuring Current
Current is measured using an ammeter.
An ammeter is connected in series with the component being measured.
Because the current is the same throughout a series circuit, ammeters placed at different positions should give approximately the same reading.
For example:
A₁ = 0.50 A
A₂ = 0.50 A
A₃ = 0.50 A
Small differences in a real experiment may occur because of measurement uncertainty.
Voltage in a Series Circuit
Voltage behaves differently from current.
The supply voltage is shared between the components.
For a series circuit:
V_total = V₁ + V₂ + V₃ + ...
For example, suppose a battery provides:
12 V
and two resistors have voltage drops of:
V₁ = 4 V
V₂ = 8 V
Then:
V_total = 4 + 8
V_total = 12 V
What Does a Voltage Drop Mean?
A voltage drop represents energy transferred per unit charge by a component.
As charge moves through a resistor, electrical energy may be transferred into:
- thermal energy
- light
- sound
- mechanical energy
- other forms
A component with a larger voltage drop transfers more energy per unit charge.
Measuring Voltage
Voltage is measured using a voltmeter.
Unlike an ammeter, a voltmeter is connected in parallel across a component.
For example, if two resistors are connected in series, separate voltmeter readings might be:
V₁ = 3 V
V₂ = 6 V
If the power supply is 9 V:
V₁ + V₂ = V_supply
3 + 6 = 9 V
Resistance in Series
When resistors are connected in series, their resistances add.
R_total = R₁ + R₂ + R₃ + ...
For example:
R₁ = 4 Ω
R₂ = 6 Ω
Then:
R_total = 4 + 6
R_total = 10 Ω
If a third resistor of 5 Ω is added:
R_total = 4 + 6 + 5
R_total = 15 Ω
Why Do Series Resistances Add?
Each resistor provides additional opposition to the movement of charge.
A charge moving around the circuit must pass through:
- resistor 1
- then resistor 2
- then resistor 3
Adding another resistor therefore creates additional resistance along the only available path.
This means:
adding resistance in series always increases the total resistance.
Equivalent Resistance
Several resistors can be replaced mathematically by a single resistor that has the same effect on the circuit.
This is called the equivalent resistance.
For resistors in series:
R_eq = R₁ + R₂ + R₃ + ...
Suppose:
R₁ = 3 Ω
R₂ = 5 Ω
R₃ = 7 Ω
Then:
R_eq = 3 + 5 + 7
R_eq = 15 Ω
The three resistors together behave like one 15 Ω resistor from the perspective of the power supply.
Equal Resistors in Series
If several identical resistors are connected in series:
R_total = nR
where:
- n = number of resistors
- R = resistance of each resistor
For example, four 10 Ω resistors give:
R_total = 4 × 10
R_total = 40 Ω
Combining Series Resistance with Ohm's Law
Once the equivalent resistance is known, Ohm's Law can be applied to the entire circuit.
V = IR
or:
I = V/R
Suppose:
V_supply = 12 V
R₁ = 2 Ω
R₂ = 4 Ω
First calculate total resistance:
R_total = 2 + 4
R_total = 6 Ω
Then calculate current:
I = V/R
I = 12/6
I = 2 A
Since this is a series circuit:
I₁ = I₂ = 2 A
Finding Individual Voltage Drops
Continue with the previous circuit:
I = 2 A
R₁ = 2 Ω
R₂ = 4 Ω
For resistor 1:
V₁ = IR₁
V₁ = 2 × 2
V₁ = 4 V
For resistor 2:
V₂ = IR₂
V₂ = 2 × 4
V₂ = 8 V
Check:
V₁ + V₂ = V_supply
4 + 8 = 12 V
The calculation is consistent.
Larger Resistance Gets a Larger Voltage Drop
In a series circuit, the same current flows through every resistor.
Since:
V = IR
a larger resistance produces a larger voltage drop.
In the previous example:
2 Ω resistor → 4 V
4 Ω resistor → 8 V
The 4 Ω resistor has twice the resistance, so it has twice the voltage drop.
Therefore, for resistors in series:
V₁/V₂ = R₁/R₂
Voltage Division
The sharing of supply voltage between series resistors is called voltage division.
For a resistor R₁:
V₁ = V_total × R₁/R_total
Suppose:
V_total = 15 V
R₁ = 2 Ω
R₂ = 3 Ω
Total resistance:
R_total = 5 Ω
Voltage across R₁:
V₁ = 15 × 2/5
V₁ = 6 V
Voltage across R₂:
V₂ = 15 × 3/5
V₂ = 9 V
Check:
6 + 9 = 15 V
Equal Resistors Share Voltage Equally
Suppose three identical resistors are connected in series across a 12 V supply.
Because their resistances are equal, their voltage drops are equal.
Therefore:
V_each = 12/3
V_each = 4 V
This principle is useful when analyzing circuits containing identical components.
Worked Example: Three Resistors
A circuit contains:
V_supply = 24 V
R₁ = 2 Ω
R₂ = 4 Ω
R₃ = 6 Ω
First calculate total resistance:
R_total = 2 + 4 + 6
R_total = 12 Ω
Calculate current:
I = V/R
I = 24/12
I = 2 A
The current through every resistor is:
2 A
Now calculate the voltage drops.
V₁ = 2 × 2 = 4 V
V₂ = 2 × 4 = 8 V
V₃ = 2 × 6 = 12 V
Check:
4 + 8 + 12 = 24 V
Everything agrees with the series circuit rules.
Predicting the Effect of Adding a Resistor
Suppose a series circuit initially contains:
V = 12 V
R = 4 Ω
Current:
I = 12/4
I = 3 A
Now add another 2 Ω resistor in series.
New total resistance:
R_total = 4 + 2
R_total = 6 Ω
New current:
I = 12/6
I = 2 A
Therefore:
adding a resistor in series increases total resistance and decreases current.
What Happens to Lamps?
Suppose identical lamps are connected in series to a battery.
Adding another lamp:
- increases total resistance
- decreases the circuit current
- changes how the supply voltage is shared
- generally makes each identical lamp dimmer
This is one reason household lighting is not normally wired as a simple series circuit.
What Happens If a Component Is Removed?
A series circuit has only one path.
If a component is removed and the circuit becomes open:
current stops everywhere in the circuit.
The same occurs if a lamp filament breaks.
One break interrupts the entire current path.
This is an important disadvantage of series connections in some applications.
Adding Cells in Series
Cells can also be connected in series.
When correctly oriented in the same direction, their voltages add.
For example, two 1.5 V cells in series provide approximately:
V_total = 1.5 + 1.5 = 3.0 V
Three such cells provide:
4.5 V
A greater supply voltage can produce a greater current if the resistance remains unchanged.
Analyzing an Unknown Series Circuit
Suppose:
V_supply = 18 V
R₁ = 3 Ω
R₂ = 6 Ω
R₃ = 9 Ω
Calculate equivalent resistance:
R_total = 3 + 6 + 9
R_total = 18 Ω
Calculate current:
I = 18/18
I = 1 A
Therefore:
I₁ = I₂ = I₃ = 1 A
Voltage drops:
V₁ = 1 × 3 = 3 V
V₂ = 1 × 6 = 6 V
V₃ = 1 × 9 = 9 V
Check:
3 + 6 + 9 = 18 V
Finding an Unknown Resistance
A 20 V supply is connected to two series resistors.
The current is:
I = 2 A
One resistor has:
R₁ = 4 Ω
First calculate the total resistance:
R_total = V/I
R_total = 20/2
R_total = 10 Ω
Since:
R_total = R₁ + R₂
10 = 4 + R₂
Therefore:
R₂ = 6 Ω
Finding an Unknown Voltage
Three resistors are connected in series.
The supply voltage is:
V_total = 18 V
Two measured voltage drops are:
V₁ = 5 V
V₂ = 7 V
Find V₃.
Use:
V_total = V₁ + V₂ + V₃
18 = 5 + 7 + V₃
18 = 12 + V₃
Therefore:
V₃ = 6 V
Finding an Unknown Current
A 9 V battery is connected to two series resistors:
R₁ = 10 Ω
R₂ = 20 Ω
Total resistance:
R_total = 10 + 20
R_total = 30 Ω
Current:
I = V/R
I = 9/30
I = 0.30 A
Because it is a series circuit:
I₁ = I₂ = 0.30 A
Power in Series Circuits
Electrical power can be calculated using:
P = VI
or:
P = I²R
Since the current is the same through series resistors, a resistor with greater resistance dissipates more power:
P = I²R
For the same current:
larger R → larger P
This also explains why the higher-resistance resistor has the larger voltage drop.
Example: Comparing Power
Two series resistors carry a current of 2 A.
R₁ = 3 Ω
R₂ = 6 Ω
For R₁:
P₁ = I²R₁
P₁ = 2² × 3
P₁ = 12 W
For R₂:
P₂ = 2² × 6
P₂ = 24 W
The 6 Ω resistor transfers twice as much energy per second.
Investigating Series Circuits Experimentally
A laboratory investigation can test the theoretical rules for series circuits.
Students might construct a circuit containing:
- power supply
- two resistors
- ammeter
- voltmeter
- switch
Measurements can then be made for:
- current before the first resistor
- current between the resistors
- current after the second resistor
- voltage across each resistor
- total supply voltage
Expected Experimental Results
Theory predicts:
I₁ = I₂ = I₃
and:
V_supply = V₁ + V₂ + V₃
It also predicts:
R_total = R₁ + R₂ + R₃
Real experimental values should be close to these predictions.
However, they may not be exactly equal.
Comparing Theory and Experiment
Suppose theory predicts:
I = 0.500 A
but the experiment gives:
I = 0.487 A
The values are close, but not identical.
Possible reasons include:
- resistor tolerances
- internal resistance of the power supply
- resistance of connecting wires
- contact resistance
- temperature changes
- meter uncertainty
- reading uncertainty
Real circuits are not perfectly ideal.
Resistor Tolerance
A resistor labelled:
100 Ω ± 5%
does not necessarily have a resistance of exactly 100 Ω.
Its actual resistance could be approximately between:
95 Ω and 105 Ω.
Therefore, theoretical calculations using exactly 100 Ω may differ slightly from experimental measurements.
Percentage Difference
A useful way to compare experimental and theoretical values is:
percentage difference = |experimental − theoretical| / theoretical × 100%
Suppose:
theoretical current = 0.500 A
experimental current = 0.487 A
Difference:
|0.487 − 0.500| = 0.013 A
Percentage difference:
0.013/0.500 × 100%
= 2.6%
A relatively small percentage difference suggests that the experimental result agrees reasonably well with the theoretical prediction.
Example: Experimental Voltage Measurements
Suppose a 12 V supply is connected to three resistors.
Experimental voltage measurements are:
V₁ = 2.1 V
V₂ = 3.8 V
V₃ = 6.0 V
Add them:
V_total = 2.1 + 3.8 + 6.0
V_total = 11.9 V
The measured supply may be approximately 12.0 V.
The 0.1 V difference could result from experimental uncertainty.
The measurements therefore provide good evidence for:
V_supply ≈ V₁ + V₂ + V₃
Ideal vs Real Circuits
In theoretical problems, we often assume:
- wires have zero resistance
- meters are perfect
- batteries maintain exactly their stated voltage
- resistors have exact resistance
- temperature remains constant
Real circuits do not perfectly satisfy these assumptions.
Therefore:
theoretical result ≈ experimental result
is often more realistic than expecting exact equality.
Kirchhoff's Rules and Series Circuits
The basic rules of series circuits are consistent with more general circuit laws.
Conservation of charge explains why the current is the same throughout a series circuit.
Charge entering a component cannot simply disappear.
Conservation of energy explains why the voltage drops add to the supply voltage.
The energy supplied to each unit of charge is transferred among the components as the charge moves around the circuit.
Series Circuit Problem-Solving Strategy
When analyzing a series circuit:
Identify the components
Determine which resistors are connected in series.
Find total resistance
Use:
R_total = R₁ + R₂ + R₃ + ...
Find circuit current
Use:
I = V_total/R_total
Use the same current everywhere
For a series circuit:
I₁ = I₂ = I₃
Find voltage drops
Use:
V = IR
for each resistor.
Check the voltage
Make sure:
V₁ + V₂ + V₃ = V_supply
This final check is very useful for detecting calculation errors.
Complete Worked Example
A 30 V power supply is connected to three resistors in series:
R₁ = 3 Ω
R₂ = 5 Ω
R₃ = 7 Ω
Total resistance
R_total = 3 + 5 + 7
R_total = 15 Ω
Circuit current
I = V/R
I = 30/15
I = 2 A
Therefore:
I₁ = I₂ = I₃ = 2 A
Voltage across R₁
V₁ = 2 × 3
V₁ = 6 V
Voltage across R₂
V₂ = 2 × 5
V₂ = 10 V
Voltage across R₃
V₃ = 2 × 7
V₃ = 14 V
Check
V_total = 6 + 10 + 14
V_total = 30 V
The results satisfy all three major series circuit rules.
Predicting Changes
Suppose the supply voltage remains constant.
If another resistor is added in series:
total resistance increases
Therefore:
current decreases
Since the current through every component decreases, the voltage drops across the original resistors may also change.
For identical lamps, this generally means:
adding lamps in series → lamps become dimmer
Removing a Resistor
If a resistor is removed but the circuit is reconnected so that it remains closed:
total resistance decreases
For constant supply voltage:
current increases
If instead the component is simply removed and leaves a gap:
the circuit becomes open and current becomes zero.
These are two different situations and should not be confused.
Common Mistakes
Mistake: Thinking current is divided between series components.
Current is the same throughout a series circuit.
Mistake: Thinking voltage is the same across every series component.
The supply voltage is shared according to resistance.
Mistake: Forgetting to add resistances.
For series resistors:
R_total = R₁ + R₂ + ...
Mistake: Saying current is used up.
Charge is conserved. Energy is transferred, but current does not gradually disappear around the circuit.
Mistake: Assuming voltage divides equally.
Voltage divides equally only when the resistances are equal.
Mistake: Adding another series resistor and predicting greater current.
Adding resistance decreases current if the supply voltage remains constant.
Mistake: Expecting experimental measurements to match theory perfectly.
Real components and measuring instruments have uncertainties and non-ideal behavior.
Mistake: Connecting a voltmeter in series.
Voltmeters are connected in parallel across components.
Key Terms
Series circuit — circuit in which components form one continuous current path.
Current — rate of flow of electric charge.
Potential difference — energy transferred per unit charge.
Voltage drop — potential difference across a circuit component.
Resistance — opposition to electric current.
Equivalent resistance — single resistance that has the same overall effect as several resistors.
Ohm's Law — relationship V = IR for an ohmic conductor under constant physical conditions.
Ammeter — instrument used to measure current and connected in series.
Voltmeter — instrument used to measure potential difference and connected in parallel.
Voltage divider — series arrangement in which the supply voltage is divided among resistors.
Open circuit — incomplete circuit in which current cannot flow around the complete path.
Resistor tolerance — permitted difference between a resistor's labelled and actual resistance.
Experimental uncertainty — range of possible uncertainty associated with a measured value.
Theoretical value — value predicted using a mathematical model or physical law.
Experimental value — value obtained through measurement.
Key Takeaways
- A series circuit contains only one path for electric current.
- Current is the same throughout a series circuit.
- I_total = I₁ = I₂ = I₃
- The supply voltage is shared between series components.
- V_total = V₁ + V₂ + V₃
- Series resistances add together.
- R_total = R₁ + R₂ + R₃
- Equivalent resistance represents the combined effect of all the resistors.
- Adding another resistor in series increases total resistance.
- If supply voltage remains constant, increasing resistance decreases current.
- Larger series resistors have larger voltage drops because the same current passes through them.
- Equal resistors divide the supply voltage equally.
- Ohm's Law can be combined with series circuit rules to calculate unknown values.
- A break anywhere in a series circuit stops current everywhere.
- Voltage division can be used to predict the voltage across individual resistors.
- Experimental results should be compared with theoretical predictions.
- Small differences between theory and experiment can result from component tolerances, temperature changes and measurement uncertainty.
- The constant current in a series circuit is consistent with conservation of charge.
- The sum of voltage drops equalling the supply voltage is consistent with conservation of energy.
Check Your Understanding
- What is meant by a series circuit?
- Describe the current at different points in a series circuit.
- Three resistors carry a current of 0.8 A in series. What is the current through each resistor?
- State the equation for total resistance in a series circuit.
- Calculate the equivalent resistance of 3 Ω, 7 Ω and 10 Ω connected in series.
- Four identical 15 Ω resistors are connected in series. Calculate the total resistance.
- A 12 V supply is connected to a total resistance of 6 Ω. Calculate the current.
- Two resistors of 2 Ω and 4 Ω are connected in series across 12 V. Calculate the circuit current.
- For Question 8, calculate the voltage across each resistor.
- Explain why the 4 Ω resistor in Question 8 has a larger voltage drop.
- Three identical resistors are connected in series across 18 V. What is the voltage across each resistor?
- A 5 Ω resistor and a 10 Ω resistor are connected in series across 30 V. Calculate the total resistance, current and voltage across each resistor.
- Predict what happens to total resistance when another resistor is added in series.
- Predict what happens to current when another resistor is added while supply voltage remains constant.
- Explain why identical lamps generally become dimmer when more are connected in series.
- Explain what happens if one lamp in a simple series circuit breaks.
- A theoretical current is 0.80 A and an experimental current is 0.76 A. Calculate the percentage difference.
- Give three reasons why experimental and theoretical circuit results may differ slightly.
- Explain why the current rule for series circuits is connected to conservation of charge.
- Explain why the sum of the voltage drops should equal the supply voltage.
4. Parallel Circuits
Learning outcomes
- I can describe voltage and current in parallel circuits.
- I can calculate equivalent resistance.
- I can explain current division.
- I can analyze parallel networks.
- I can compare series and parallel circuits.
Parallel Circuits
What Is a Parallel Circuit?
A parallel circuit contains two or more separate paths, called branches, through which electric current can flow.
At a junction, current can divide between the branches. The currents then recombine when the branches join again.
The main rules for a parallel circuit are:
Voltage is the same across each parallel branch.
Current divides between the branches.
The total current equals the sum of the branch currents.
Adding parallel branches decreases the equivalent resistance.
These rules make parallel circuits behave very differently from series circuits.
Voltage in a Parallel Circuit
Components connected in parallel are connected between the same two points in the circuit.
Therefore, they have the same potential difference.
For parallel branches:
V_total = V₁ = V₂ = V₃ = ...
Suppose two resistors are connected in parallel across a 12 V battery.
Then:
V₁ = 12 V
V₂ = 12 V
The voltage is not divided between the branches.
Each branch receives the full supply voltage.
Why Is the Voltage the Same?
Potential difference measures the energy transferred per unit charge between two points.
Parallel branches begin and end at the same two electrical points.
Therefore, the potential difference between the ends of each branch must be the same.
If three lamps are connected in parallel across a 9 V supply, each lamp has approximately:
9 V across it
This is one major advantage of parallel circuits.
Measuring Voltage
A voltmeter is connected in parallel across the component whose potential difference is being measured.
If two resistors are connected in parallel across a 6 V supply, measurements should show approximately:
V_supply = 6 V
V₁ = 6 V
V₂ = 6 V
Small differences may occur in a real experiment because of measurement uncertainty and non-ideal components.
Current in a Parallel Circuit
Current behaves differently from voltage.
At a junction, the current splits between the available branches.
The total current entering a junction must equal the total current leaving it.
For a simple parallel circuit:
I_total = I₁ + I₂ + I₃ + ...
For example:
I₁ = 2 A
I₂ = 3 A
Then:
I_total = 2 + 3
I_total = 5 A
Conservation of Charge
The current rule for parallel circuits follows from the conservation of charge.
Charge cannot simply disappear at a junction.
If 5 coulombs of charge arrive at a junction each second, a total of 5 coulombs per second must leave through the branches.
For example:
3 C/s may travel through one branch
and:
2 C/s may travel through another.
Since:
1 A = 1 C/s
the currents are:
3 A + 2 A = 5 A
Current Division
Current does not necessarily divide equally between parallel branches.
The amount of current in each branch depends on the branch resistance.
Using Ohm's Law:
I = V/R
Since each branch has the same voltage:
lower resistance → greater current
higher resistance → smaller current
This is called current division.
Example of Current Division
Two resistors are connected in parallel across 12 V.
R₁ = 4 Ω
R₂ = 6 Ω
Current through R₁:
I₁ = V/R₁
I₁ = 12/4
I₁ = 3 A
Current through R₂:
I₂ = 12/6
I₂ = 2 A
Total current:
I_total = I₁ + I₂
I_total = 3 + 2
I_total = 5 A
Notice that the lower-resistance branch carries the larger current.
Equal Resistances
If two identical resistors are connected in parallel, the current divides equally.
Suppose two 10 Ω resistors are connected across 20 V.
Current through each resistor:
I = V/R
I = 20/10
I = 2 A
Therefore:
I₁ = 2 A
I₂ = 2 A
Total current:
I_total = 4 A
Equal resistances produce equal branch currents.
Measuring Current
Current is measured using an ammeter.
An ammeter must be connected in series with the path whose current is being measured.
An ammeter placed before the junction measures:
total current
An ammeter placed inside one branch measures:
branch current
An ammeter after the branches recombine again measures:
total current
Equivalent Resistance in Parallel
Several parallel resistors can be replaced mathematically by a single equivalent resistance.
For resistors in parallel:
1/R_total = 1/R₁ + 1/R₂ + 1/R₃ + ...
This rule is very different from the series resistance rule.
In parallel:
the equivalent resistance is always less than the smallest individual branch resistance.
Calculating Equivalent Resistance
Suppose:
R₁ = 6 Ω
R₂ = 3 Ω
Then:
1/R_total = 1/6 + 1/3
Convert to a common denominator:
1/R_total = 1/6 + 2/6
1/R_total = 3/6
1/R_total = 1/2
Therefore:
R_total = 2 Ω
Notice:
2 Ω is smaller than both 3 Ω and 6 Ω.
Why Does Parallel Resistance Decrease?
Adding a parallel branch gives charge another path through the circuit.
More pathways allow more total current to flow for the same supply voltage.
From Ohm's Law:
R = V/I
If V remains constant while total I increases, the equivalent resistance must decrease.
Therefore:
more parallel paths → lower equivalent resistance
Two-Resistor Shortcut
For exactly two resistors in parallel:
R_total = (R₁R₂)/(R₁ + R₂)
For example:
R₁ = 4 Ω
R₂ = 12 Ω
Then:
R_total = (4 × 12)/(4 + 12)
R_total = 48/16
R_total = 3 Ω
This shortcut works only for two parallel resistors.
Equal Resistors in Parallel
If n identical resistors, each with resistance R, are connected in parallel:
R_total = R/n
For example, three identical 12 Ω resistors are connected in parallel.
R_total = 12/3
R_total = 4 Ω
Four identical 20 Ω resistors would give:
R_total = 20/4
R_total = 5 Ω
Checking Your Parallel Resistance Answer
A useful check is:
R_total must be smaller than the smallest branch resistance.
Suppose you calculate the equivalent resistance of:
10 Ω and 15 Ω
and obtain:
25 Ω
That cannot be correct.
Since the resistors are in parallel, the answer must be:
less than 10 Ω
The correct calculation is:
R_total = (10 × 15)/(10 + 15)
R_total = 150/25
R_total = 6 Ω
Analyzing a Complete Parallel Circuit
Suppose two resistors are connected in parallel across 12 V:
R₁ = 6 Ω
R₂ = 4 Ω
Voltage
Because the resistors are parallel:
V₁ = V₂ = 12 V
Branch currents
I₁ = 12/6
I₁ = 2 A
I₂ = 12/4
I₂ = 3 A
Total current
I_total = 2 + 3
I_total = 5 A
Equivalent resistance
R_total = V_total/I_total
R_total = 12/5
R_total = 2.4 Ω
Check using the parallel formula:
1/R_total = 1/6 + 1/4
1/R_total = 2/12 + 3/12
1/R_total = 5/12
R_total = 12/5
R_total = 2.4 Ω
Both methods agree.
Three Resistors in Parallel
Consider:
V = 12 V
R₁ = 4 Ω
R₂ = 6 Ω
R₃ = 12 Ω
Since all branches have the same voltage:
V₁ = V₂ = V₃ = 12 V
Calculate branch currents:
I₁ = 12/4 = 3 A
I₂ = 12/6 = 2 A
I₃ = 12/12 = 1 A
Total current:
I_total = 3 + 2 + 1
I_total = 6 A
Equivalent resistance:
R_total = V/I
R_total = 12/6
R_total = 2 Ω
Again, the equivalent resistance is smaller than the smallest branch resistance of 4 Ω.
Predicting the Effect of Adding a Branch
Suppose a battery maintains a constant voltage.
Adding another resistor in parallel:
- creates another current path
- decreases equivalent resistance
- increases total current supplied by the battery
This is the opposite of adding another resistor in series.
Series
Add resistor → R_total increases → I_total decreases
Parallel
Add branch → R_total decreases → I_total increases
This is one of the most important comparisons between the two circuit types.
What Happens to Existing Branches?
Suppose an ideal 12 V source has one 6 Ω resistor connected across it.
Current:
I = 12/6
I = 2 A
Now add another 6 Ω resistor in parallel.
Each branch still has:
12 V
Each branch therefore still carries:
2 A
But the total current becomes:
I_total = 2 + 2
I_total = 4 A
So adding the second branch increases the current supplied by the source without changing the current through the original resistor, assuming an ideal constant-voltage source.
Lamps in Parallel
When identical lamps are connected in parallel:
- each lamp receives the full supply voltage
- each lamp can operate approximately as it would alone
- adding another lamp increases the total current
- removing one lamp does not necessarily turn off the others
This is very different from a series circuit.
If One Parallel Branch Breaks
Suppose three lamps are connected in parallel.
If one lamp fails, that branch becomes open.
Current stops through that branch.
However, the other branches still provide complete paths through the circuit.
Therefore, the other lamps can continue operating.
This is an important advantage of parallel circuits.
Household Circuits
Electrical devices in buildings are connected mainly in parallel.
This means different appliances receive approximately the same supply voltage and can operate independently.
Switching off one device does not normally interrupt the current through all the others.
Parallel connections therefore provide much greater independence than a single series circuit.
Comparing Series and Parallel Circuits
| Property | Series | Parallel |
|---|---|---|
| Current paths | One | Two or more |
| Current | Same everywhere | Divides between branches |
| Voltage | Divided between components | Same across branches |
| Resistance | R_total = R₁ + R₂ + ... | Reciprocal rule |
| Adding resistor | Increases R_total | Decreases R_total |
| Adding resistor at fixed V | Decreases total current | Increases total current |
| One component fails | Whole path may break | Other branches can continue |
| Common use | Some simple circuits | Household/electrical systems |
Current Division and Resistance
For two parallel resistors:
R₁ and R₂
the currents are:
I₁ = V/R₁
I₂ = V/R₂
Since V is the same:
I₁/I₂ = R₂/R₁
This means the current ratio is the inverse of the resistance ratio.
For example:
R₁ = 3 Ω
R₂ = 6 Ω
Then:
I₁/I₂ = 6/3
I₁/I₂ = 2
So the 3 Ω branch carries twice the current of the 6 Ω branch.
Worked Current Division Example
A total current of 6 A enters two parallel branches.
The resistances are:
R₁ = 4 Ω
R₂ = 8 Ω
The 4 Ω branch has half the resistance, so it carries twice the current.
The currents must add to 6 A.
Therefore:
I₁ = 4 A
I₂ = 2 A
Check:
4 + 2 = 6 A
We can also determine the branch voltage:
V = I₁R₁
V = 4 × 4
V = 16 V
Check the second branch:
V = 2 × 8
V = 16 V
The voltage is the same across both branches, as expected.
Finding an Unknown Branch Current
A total current of 8 A reaches a junction.
One branch carries 3 A.
Another carries 2 A.
A third branch carries I₃.
Use:
I_total = I₁ + I₂ + I₃
8 = 3 + 2 + I₃
8 = 5 + I₃
Therefore:
I₃ = 3 A
This is an application of conservation of charge.
Finding an Unknown Resistance
Two resistors are connected in parallel across 12 V.
The total current is 5 A.
One branch contains:
R₁ = 4 Ω
First calculate current through R₁:
I₁ = 12/4
I₁ = 3 A
Total current:
I_total = I₁ + I₂
5 = 3 + I₂
Therefore:
I₂ = 2 A
Now:
R₂ = V/I₂
R₂ = 12/2
R₂ = 6 Ω
Mixed Series-Parallel Networks
Some circuits contain both series and parallel connections.
The best strategy is to simplify the circuit one section at a time.
For example, suppose:
R₁ = 4 Ω
R₂ = 6 Ω
are connected in parallel, and this combination is connected in series with:
R₃ = 5 Ω
First find the parallel equivalent:
R_parallel = (4 × 6)/(4 + 6)
R_parallel = 24/10
R_parallel = 2.4 Ω
Now add the series resistor:
R_total = 2.4 + 5
R_total = 7.4 Ω
The entire network therefore behaves like a 7.4 Ω resistance.
Strategy for Analyzing Parallel Networks
When solving a parallel circuit:
Identify the branches
Determine which components share the same two connection points.
Use equal voltage
For parallel branches:
V₁ = V₂ = V₃
Calculate branch currents
Use:
I = V/R
for each branch.
Add the currents
Use:
I_total = I₁ + I₂ + I₃
Calculate equivalent resistance
Use either:
1/R_total = 1/R₁ + 1/R₂ + ...
or:
R_total = V_total/I_total
Check your answer
Make sure:
R_total < smallest branch resistance
This is a very useful error check.
Series-Parallel Analysis Strategy
For a mixed network:
- Identify simple series or parallel groups.
- Replace one group with its equivalent resistance.
- Redraw or mentally simplify the circuit.
- Continue until one total resistance remains.
- Calculate total current.
- Work backward through the circuit.
- Use series and parallel rules to find individual currents and voltages.
This approach prevents complicated networks from becoming overwhelming.
Power in Parallel Circuits
Electrical power can be calculated using:
P = VI
For a resistor:
P = V²/R
Since parallel branches have the same voltage, a lower-resistance branch dissipates more power.
For example, two resistors are connected across 12 V:
R₁ = 6 Ω
R₂ = 12 Ω
For R₁:
P₁ = 12²/6
P₁ = 144/6
P₁ = 24 W
For R₂:
P₂ = 144/12
P₂ = 12 W
The lower-resistance branch carries more current and transfers more energy per second.
Experimental Investigation
A parallel circuit can be investigated using ammeters and voltmeters.
Measurements can test whether:
V_supply ≈ V₁ ≈ V₂
and:
I_total ≈ I₁ + I₂
Small differences may occur because of:
- meter uncertainty
- resistor tolerances
- connecting-wire resistance
- contact resistance
- internal resistance of the source
- temperature changes
Parallel Circuits and Conservation Laws
The two major parallel circuit rules are connected to fundamental physical principles.
Conservation of charge
At a junction:
current entering = current leaving
This explains:
I_total = I₁ + I₂ + ...
Conservation of energy
Branches connected between the same two points have the same energy change per unit charge.
This explains:
V_total = V₁ = V₂ = ...
These rules are not arbitrary—they follow from fundamental conservation principles.
Why Parallel Resistance Can Seem Strange
Students sometimes find it surprising that connecting two resistors produces an equivalent resistance smaller than either resistor.
Consider two 10 Ω resistors.
One resistor alone:
R = 10 Ω
Two in series:
R = 20 Ω
Two in parallel:
R = 5 Ω
The parallel arrangement has two simultaneous pathways for current.
This allows twice as much total current for the same voltage.
Since:
R = V/I
doubling current while maintaining voltage halves the equivalent resistance.
Series vs Parallel Example
Suppose two identical 6 Ω resistors are connected to a 12 V source.
In series
R_total = 6 + 6
R_total = 12 Ω
I_total = 12/12
I_total = 1 A
Each resistor carries:
1 A
Each has:
6 V
across it.
In parallel
R_total = 6/2
R_total = 3 Ω
I_total = 12/3
I_total = 4 A
Each branch has:
12 V
Current through each branch:
I = 12/6
I = 2 A
The same components behave very differently depending on how they are connected.
Common Mistakes
Mistake: Saying current is the same in every parallel branch.
Current divides according to branch resistance.
Mistake: Saying voltage divides between parallel branches.
Parallel branches have the same voltage.
Mistake: Adding parallel resistances directly.
The direct addition rule applies to series circuits.
Mistake: Obtaining an equivalent resistance larger than the smallest branch resistance.
Parallel equivalent resistance must be smaller than the smallest individual resistance.
Mistake: Assuming current divides equally.
It divides equally only when branch resistances are equal.
Mistake: Thinking current is lost at a junction.
Total current entering equals total current leaving.
Mistake: Thinking adding a parallel resistor increases total resistance.
Adding another parallel path decreases equivalent resistance.
Mistake: Applying the two-resistor shortcut to three or more resistors.
Use the reciprocal formula for larger networks.
Key Terms
Parallel circuit — circuit containing two or more separate paths for current.
Branch — individual path within a parallel circuit.
Junction — point where current paths divide or recombine.
Branch current — current flowing through one parallel path.
Total current — combined current supplied to all branches.
Equivalent resistance — single resistance that produces the same overall circuit behavior as a network of resistors.
Current division — splitting of current among parallel branches.
Potential difference — energy transferred per unit charge.
Ohm's Law — relationship V = IR for an ohmic conductor under constant physical conditions.
Conservation of charge — principle that electric charge cannot be created or destroyed in an ordinary circuit.
Mixed circuit — circuit containing both series and parallel connections.
Open branch — branch with a break that prevents current from flowing through it.
Key Takeaways
- Parallel circuits contain two or more current paths.
- Voltage is the same across parallel branches.
- V_total = V₁ = V₂ = V₃
- Current divides at junctions.
- I_total = I₁ + I₂ + I₃
- Lower-resistance branches carry greater current.
- Equal resistances carry equal currents when connected in parallel.
- Parallel equivalent resistance is calculated using the reciprocal rule.
- For two resistors, R_total = R₁R₂/(R₁ + R₂).
- The equivalent resistance is always smaller than the smallest parallel resistance.
- Adding another parallel branch decreases equivalent resistance.
- At constant supply voltage, adding a parallel branch increases total current.
- Existing ideal parallel branches continue to receive the full supply voltage.
- If one parallel branch breaks, the other branches can continue operating.
- Household electrical systems use parallel connections so devices can operate independently.
- Current division follows from Ohm's Law and the equal voltage across branches.
- The current rule follows from conservation of charge.
- Parallel networks can be combined with series sections to create mixed circuits.
- Complex networks can be analyzed by simplifying one section at a time.
- Series and parallel circuits behave very differently even when they contain the same components.
Check Your Understanding
- What is meant by a parallel circuit?
- Describe the voltage across different branches of a parallel circuit.
- Describe what happens to current at a junction.
- A total current of 8 A divides into branches carrying 3 A and 5 A. Show that charge is conserved.
- A total current of 10 A divides into three branches. Two carry 2 A and 3 A. Calculate the third current.
- Two resistors of 6 Ω and 3 Ω are connected in parallel. Calculate the equivalent resistance.
- Two resistors of 4 Ω and 12 Ω are connected in parallel. Calculate the equivalent resistance.
- Three identical 15 Ω resistors are connected in parallel. Calculate the equivalent resistance.
- Why must parallel equivalent resistance be smaller than the smallest branch resistance?
- Two resistors of 4 Ω and 8 Ω are connected across 16 V. Calculate the current through each branch.
- For Question 10, calculate the total current.
- Explain why the 4 Ω resistor carries more current than the 8 Ω resistor.
- What happens to equivalent resistance when another parallel branch is added?
- What happens to total current when another branch is added while supply voltage remains constant?
- Explain what happens to the other lamps if one lamp in a parallel lighting circuit fails.
- Compare voltage in series and parallel circuits.
- Compare current in series and parallel circuits.
- Compare the effect of adding a resistor in series with adding a resistor in parallel.
- A 5 Ω resistor is connected in series with two 12 Ω resistors connected in parallel. Calculate the total equivalent resistance.
- Explain why parallel circuits are generally more suitable than simple series circuits for connecting independent electrical devices.
5. Measuring Electrical Quantities
Learning outcomes
- I can correctly use ammeters and voltmeters.
- I can measure current and voltage safely.
- I can interpret measurement data.
- I can identify common measurement errors.
- I can evaluate experimental results.