Power and Efficiency
| Site: | Young Education |
| Cours: | Work Energy Power |
| Livre: | Power and Efficiency |
| Imprimé par: | Guest user |
| Date: | lundi, 9 novembre 2026, 16:40 |
1. Power
Learning outcomes
- I can define power as the rate at which work is done or energy is transferred.
- I can explain the difference between energy and power.
- I can recall and use the equation \( P = \frac{E}{t} \)
- I can calculate power from energy transfers and time intervals.
- I can compare the power outputs of different devices and systems.
Power
Power is the rate at which work is done or energy is transferred.
Power tells us how quickly energy is transferred.
Two machines can transfer exactly the same amount of energy but have very different power outputs if one transfers the energy in less time.
For example:
- two people climb the same staircase, but one runs while the other walks
- two kettles heat the same amount of water, but one heats it faster
- two motors lift the same load, but one completes the lift more quickly
- two lamps transfer energy continuously but at different rates
The faster energy is transferred, the greater the power.
Energy and Power Are Different
Energy and power are closely related, but they are not the same quantity.
Energy describes how much energy is transferred or stored.
Power describes how quickly that energy is transferred.
For example, suppose two motors each transfer 10,000 J of energy.
Motor A takes:
20 s
Motor B takes:
5 s
They transfer the same amount of energy, but Motor B transfers it much faster.
Therefore, Motor B has the greater power.
The Power Equation
Power can be calculated using:
P = E/t
where:
- P = power in watts (W)
- E = energy transferred in joules (J)
- t = time in seconds (s)
Power can also be expressed as:
P = W/t
where W represents work done, not watts.
This means:
power = energy transferred ÷ time
or:
power = work done ÷ time
The Watt
The SI unit of power is the watt (W).
One watt means that one joule of energy is transferred every second.
Therefore:
1 W = 1 J/s
A device operating at:
10 W
transfers:
10 J every second
A device operating at:
1000 W
transfers:
1000 J every second
Kilowatts and Megawatts
Large power values are often expressed using larger units.
1 kW = 1000 W
1 MW = 1,000,000 W
1 GW = 1,000,000,000 W
For example:
2000 W = 2 kW
5,000,000 W = 5 MW
Small electrical devices may use only a few watts, while power stations may produce hundreds or thousands of megawatts.
Worked Example: Basic Power Calculation
A machine transfers 600 J of energy in 3 s.
Calculate its power.
Use:
P = E/t
Substitute:
P = 600/3
P = 200 W
The machine has a power output of 200 W.
This means it transfers energy at a rate of:
200 J/s
Worked Example: Electric Device
An electrical device transfers 12,000 J of energy in 60 s.
P = E/t
P = 12,000/60
P = 200 W
The device operates at 200 W.
Worked Example: Larger Machine
A machine transfers 2.4 MJ of energy in 40 s.
First convert megajoules to joules:
2.4 MJ = 2,400,000 J
Then:
P = 2,400,000/40
P = 60,000 W
or:
P = 60 kW
Comparing Power
Suppose two machines perform the same task.
Machine A
Energy transferred = 5000 J
Time = 10 s
P = 5000/10
P = 500 W
Machine B
Energy transferred = 5000 J
Time = 5 s
P = 5000/5
P = 1000 W
Machine B has twice the power because it transfers the same energy in half the time.
Power and Time
For a fixed amount of energy:
shorter time → greater power
longer time → smaller power
For example:
| Energy Transferred | Time | Power |
|---|---|---|
| 1000 J | 1 s | 1000 W |
| 1000 J | 2 s | 500 W |
| 1000 J | 5 s | 200 W |
| 1000 J | 10 s | 100 W |
The total energy is identical in every case.
Only the rate of energy transfer changes.
Power and Energy
If the time remains constant:
more energy transferred → greater power
For example:
| Energy | Time | Power |
|---|---|---|
| 100 J | 10 s | 10 W |
| 200 J | 10 s | 20 W |
| 500 J | 10 s | 50 W |
| 1000 J | 10 s | 100 W |
Power is directly proportional to energy transferred when time remains constant.
Rearranging the Power Equation
Starting with:
P = E/t
we can rearrange the equation to calculate energy or time.
Finding Energy
Multiply both sides by t:
E = Pt
Finding Time
Rearrange:
t = E/P
These three forms are useful:
P = E/t
E = Pt
t = E/P
Worked Example: Finding Energy
A 500 W motor operates for 20 s.
Calculate the energy transferred.
Use:
E = Pt
E = 500 × 20
E = 10,000 J
The motor transfers 10 kJ of energy.
Worked Example: Finding Time
A machine must transfer 24,000 J of energy.
Its power is:
800 W
How long does it take?
Use:
t = E/P
t = 24,000/800
t = 30 s
Power and Work Done
Because work done represents energy transferred:
P = W/t
where:
- P = power
- W = work done
- t = time
Recall:
work done = force × distance
For a constant force acting in the direction of motion:
W = Fd
Therefore:
P = Fd/t
Since:
v = d/t
we can also write:
P = Fv
for a constant force acting in the direction of motion.
Worked Example: Lifting a Load
A motor does 15,000 J of work lifting a load in 5 s.
Calculate its power.
P = W/t
P = 15,000/5
P = 3000 W
or:
P = 3.0 kW
Power and Gravitational Potential Energy
When an object is lifted:
ΔEₚ = mgΔh
If the lift takes time t:
P = mgΔh/t
This allows us to calculate the power required to raise an object.
Worked Example: Crane
A crane lifts a 500 kg load vertically through 8 m in 10 s.
Use:
g = 9.8 N/kg
First calculate the change in gravitational potential energy:
ΔEₚ = mgΔh
ΔEₚ = 500 × 9.8 × 8
ΔEₚ = 39,200 J
Now calculate power:
P = E/t
P = 39,200/10
P = 3920 W
or:
P = 3.92 kW
Worked Example: Climbing Stairs
A 60 kg student climbs a staircase with a vertical height of 5 m in 6 s.
Use:
g = 9.8 N/kg
GPE gained:
ΔEₚ = 60 × 9.8 × 5
ΔEₚ = 2940 J
Power:
P = 2940/6
P = 490 W
The student's average mechanical power while climbing is approximately 490 W.
Comparing Two Students
Suppose two 60 kg students climb the same 5 m staircase.
Student A takes:
10 s
Student B takes:
5 s
Both gain the same GPE:
2940 J
Student A:
P = 2940/10 = 294 W
Student B:
P = 2940/5 = 588 W
Both perform the same amount of mechanical work, but Student B has twice the average power because the work is completed in half the time.
Power and Kinetic Energy
Power can also describe how quickly kinetic energy changes.
Recall:
Eₖ = ½mv²
If a motor increases an object's kinetic energy, the average power associated with that transfer is:
P = ΔEₖ/t
For an object accelerating from rest:
P = ½mv²/t
if we are calculating the average power over that time interval.
Worked Example: Accelerating a Car
A 1000 kg car accelerates from rest to 20 m/s in 10 s.
Ignore energy losses.
Final kinetic energy:
Eₖ = ½mv²
Eₖ = 0.5 × 1000 × 20²
Eₖ = 200,000 J
Average power:
P = E/t
P = 200,000/10
P = 20,000 W
or:
P = 20 kW
This is the average mechanical power transferred into kinetic energy during the acceleration.
A real engine or motor would need to provide more energy because of friction, air resistance, and other losses.
Average Power and Instantaneous Power
Power can change during a process.
The equation:
P = ΔE/Δt
usually gives average power over a time interval.
For example, a car's engine may produce different power at different moments during acceleration.
Instantaneous power describes the rate of energy transfer at one particular moment.
For many introductory problems, we calculate average power.
Electrical Devices
Electrical appliances are commonly labelled with their power.
For example, a device rated at:
1000 W
transfers approximately:
1000 J every second
while operating at that power.
A 2000 W device transfers energy twice as quickly as a 1000 W device.
Example: Electric Kettle
A kettle operates at:
2000 W
How much energy does it transfer in 3 minutes?
First convert time:
3 min = 180 s
Use:
E = Pt
E = 2000 × 180
E = 360,000 J
or:
E = 360 kJ
Example: Light Bulb
A lamp operates at 10 W for 60 s.
E = Pt
E = 10 × 60
E = 600 J
The lamp transfers 600 J of energy during that minute.
Not all of this necessarily becomes visible light. Some energy is transferred thermally.
Power Does Not Mean Total Energy
A high-power device does not necessarily transfer more total energy than a low-power device.
It depends on how long each device operates.
For example:
A 1000 W device operating for 10 s transfers:
E = 1000 × 10
E = 10,000 J
A 100 W device operating for 200 s transfers:
E = 100 × 200
E = 20,000 J
The lower-power device transferred more total energy because it operated for much longer.
This is an important distinction:
power = rate
energy = total amount transferred
Power in Vehicles
Vehicle engines and motors are often compared by their power output.
Greater power allows energy to be transferred more rapidly.
This can affect a vehicle's ability to:
- accelerate
- climb hills
- pull heavy loads
- maintain speed against resistive forces
However, power alone does not determine vehicle performance. Mass, gearing, traction, drag, efficiency, and other factors also matter.
Power in Sports
Power is important in many sports.
Activities requiring high power include:
- sprinting
- jumping
- weightlifting
- cycling
- rowing
- climbing quickly
Two athletes may perform the same amount of work, but the athlete who completes it faster produces greater average mechanical power.
Worked Example: Weightlifting
An athlete lifts a 100 kg mass vertically through 2 m in 1.5 s.
Use:
g = 9.8 N/kg
Work done against gravity:
W = mgΔh
W = 100 × 9.8 × 2
W = 1960 J
Power:
P = 1960/1.5
P ≈ 1307 W
or approximately:
1.31 kW
Power Stations
Power stations are designed to transfer enormous amounts of energy every second.
For example, a power station producing:
500 MW
has a power output of:
500,000,000 W
This means it transfers approximately:
500,000,000 J of energy every second
when operating at that output.
This demonstrates why watts are a rate, not an amount of energy.
Power and Efficiency
A device may receive energy at one power but provide useful energy at a smaller output power.
For example:
Input power = 1000 W
Useful output power = 800 W
Efficiency:
efficiency = useful output power / input power
efficiency = 800/1000
efficiency = 0.80
or:
80%
The remaining power is being transferred into other forms, often thermal energy and sound.
Worked Example: Motor Efficiency
An electric motor receives:
2500 W
of electrical power.
Its efficiency is:
80%
Useful mechanical power:
useful power = efficiency × input power
useful power = 0.80 × 2500
useful power = 2000 W
Therefore:
500 W
is being transferred into other forms while the motor operates under those conditions.
Energy Flow and Power
Energy flow diagrams can also include power.
For example:
2000 W electrical input → 1600 W useful mechanical output + 400 W thermal/sound
This means that every second:
2000 J enters
1600 J becomes useful mechanical energy
400 J is transferred elsewhere
The energy still balances.
Power and Energy Conservation
Power does not change the law of conservation of energy.
A powerful machine does not create more energy.
It simply transfers energy more rapidly.
For example, two motors may each transfer:
100 kJ
Motor A might take:
100 s
Motor B might take:
20 s
Motor A:
P = 100,000/100 = 1000 W
Motor B:
P = 100,000/20 = 5000 W
Both transfer the same energy.
Motor B simply does so five times faster.
Real-World Comparison: Kettles
Suppose two idealized kettles must transfer 300 kJ to water.
Kettle A
Power = 1000 W
t = E/P
t = 300,000/1000
t = 300 s
Kettle B
Power = 2000 W
t = 300,000/2000
t = 150 s
The higher-power kettle can transfer the required energy in half the time, assuming equal efficiency and identical conditions.
Real-World Comparison: Elevators
Consider two elevators lifting identical loads through the same height.
Both perform the same amount of work.
If Elevator A completes the lift in 20 s and Elevator B completes it in 10 s:
Elevator B has twice the average mechanical power.
This is because:
P = E/t
Halving the time while transferring the same energy doubles the power.
Power and Time Graphs
If a device operates at constant power, energy transferred increases steadily with time.
Since:
E = Pt
a graph of energy against time for constant power is a straight line.
The gradient is:
gradient = ΔE/Δt
Therefore:
gradient = power
A steeper energy-time graph represents a more powerful device.
Variable Power
Not every device operates at constant power.
Suppose a machine's power changes over time.
The total energy transferred depends on the area under a power-time graph.
For constant power:
E = Pt
which is simply:
area = height × width
For changing power, the area under the graph can still represent the total energy transferred.
This becomes useful when analyzing engines, motors, electrical systems, and changing mechanical processes.
Common Mistakes
Confusing Power with Energy
Energy is measured in:
joules (J)
Power is measured in:
watts (W)
Power describes the rate of energy transfer.
Thinking a More Powerful Device Always Uses More Energy
Not necessarily.
Energy depends on both:
power and operating time
because:
E = Pt
Forgetting to Convert Minutes to Seconds
For standard SI calculations:
1 min = 60 s
Therefore:
5 min = 300 s
Confusing Watts and Joules
Watt = power
Joule = energy
Remember:
1 W = 1 J/s
Forgetting to Convert Kilowatts
1 kW = 1000 W
Therefore:
2.5 kW = 2500 W
Using the Wrong Time
Power calculations require the time during which the specified energy transfer occurs.
Assuming Power Is the Same as Force
Power is not force.
Force is measured in:
newtons
Power is measured in:
watts
Forgetting That Power Can Change
Many calculations give average power over a time interval.
A machine's instantaneous power may vary during that interval.
Check Your Understanding
- Define power.
- Explain the difference between energy and power.
- State the equation for power.
- What is the SI unit of power?
- What does 1 W mean?
- A machine transfers 1200 J in 4 s. Calculate its power.
- A device transfers 15,000 J in 30 s. Calculate its power.
- A 2 kW machine operates for 10 s. Calculate the energy transferred.
- A 500 W device transfers 20,000 J. How long does it operate?
- Convert 3.5 kW to watts.
- Convert 2 MW to watts.
- Two machines each transfer 5000 J. Machine A takes 20 s and Machine B takes 5 s. Compare their power outputs.
- Explain why completing the same work in less time requires greater average power.
- A 50 kg student climbs vertically 4 m in 5 s. Calculate the student's average mechanical power using g = 9.8 N/kg.
- A crane lifts a 1000 kg load through 6 m in 20 s. Calculate its useful mechanical power.
- A 1500 W kettle operates for 3 minutes. Calculate the energy transferred.
- A 1000 kg car accelerates from rest to 30 m/s in 15 s. Calculate the increase in kinetic energy.
- Calculate the average power transferred into kinetic energy in Question 17.
- Why would the actual engine or motor need to transfer more energy than calculated in Question 17?
- A machine has an input power of 5000 W and a useful output power of 4000 W. Calculate its efficiency.
- A motor is 75% efficient and receives 8 kW. Calculate its useful output power.
- Explain how a high-power motor differs from a low-power motor performing the same task.
- A power station produces 300 MW. How many joules does it transfer each second?
- Explain why a 100 W device can transfer more total energy than a 1000 W device.
- Describe how power could be measured experimentally by having students climb a staircase.
Key Terms
Power — Rate at which work is done or energy is transferred.
Watt (W) — SI unit of power; one joule transferred per second.
Joule (J) — SI unit of energy.
Energy — Quantity that can be stored and transferred within physical systems.
Work done — Energy transferred when a force causes displacement.
Rate — Change in a quantity per unit time.
Kilowatt (kW) — Unit of power equal to 1000 W.
Megawatt (MW) — Unit of power equal to 1,000,000 W.
Gigawatt (GW) — Unit of power equal to 1,000,000,000 W.
Average power — Total energy transferred divided by the time interval over which the transfer occurs.
Instantaneous power — Rate of energy transfer at a particular moment.
Input power — Rate at which energy enters a device or system.
Useful output power — Rate at which energy is transferred into the desired output.
Efficiency — Fraction of input energy or power transferred into a useful output.
Energy-time graph — Graph showing how transferred energy changes with time; its gradient represents power.
Power-time graph — Graph showing how power varies with time; its area represents energy transferred.
Key Takeaways
- Power describes how quickly energy is transferred.
- Power can also be described as the rate at which work is done.
- The main equation is P = E/t.
- Power is measured in watts (W).
- One watt equals one joule per second.
- Energy and power are different quantities.
- Energy measures the amount transferred; power measures the rate of transfer.
- Two devices can transfer the same amount of energy while having different power outputs.
- For the same energy transfer, completing the process in less time requires greater average power.
- The equation can be rearranged to E = Pt and t = E/P.
- Kilowatts, megawatts, and gigawatts are commonly used for larger power values.
- Power can be combined with kinetic, gravitational potential, and elastic potential energy calculations.
- A motor lifting an object can be analyzed using P = mgΔh/t.
- Average power during acceleration can be found from P = ΔEₖ/t.
- Higher power does not automatically mean greater total energy consumption; operating time also matters.
- Efficiency can be calculated by comparing useful output power with input power.
- Real machines often have a lower useful output power than input power because some energy is dissipated.
- The gradient of an energy-time graph represents power.
- The area under a power-time graph represents energy transferred.
- Power is one of the most useful quantities for comparing how quickly different machines, devices, and people can transfer energy.
The central relationship is:
P = E/t
Remember:
same energy + less time = greater power
and:
1 W = 1 J/s
A powerful system does not necessarily transfer more total energy. It transfers energy at a faster rate.
2. Mechanical Power
Learning outcomes
- I can explain how power relates to force, displacement, and velocity.
- I can recall and use the equation \( P = \frac{W}{t} \)
- I can recall and use the equation P = Fv for constant velocity motion.
- I can calculate the mechanical power required in practical situations.
- I can analyze how force, speed, and power are related in machines and transportation systems.
3. Electrical Power
Learning outcomes
- I can describe electrical power as the rate of electrical energy transfer.
- I can recall and use the equation P = IV
- I can calculate electrical power in simple circuits.
- I can determine energy consumption from power ratings and operating times.
- I can interpret power ratings on electrical devices and explain their significance.
Electrical Power
Electrical power is the rate at which electrical energy is transferred by a device or circuit.
Every electrical device transfers energy. For example:
- a lamp transfers electrical energy into light and thermal energy
- a heater transfers electrical energy into thermal energy
- a motor transfers electrical energy into mechanical energy
- a speaker transfers electrical energy into sound
- a charger transfers electrical energy into energy stored in a battery
The power rating tells us how quickly this energy is transferred.
Electrical Power
Power is the rate of energy transfer:
P = E/t
where:
- P = power in watts (W)
- E = energy transferred in joules (J)
- t = time in seconds (s)
For electrical circuits, power can also be calculated using:
P = IV
where:
- P = electrical power (W)
- I = current (A)
- V = potential difference or voltage (V)
This is one of the most important equations for electrical circuits.
The Watt
Electrical power is measured in watts (W).
1 W = 1 J/s
Therefore, a 60 W device transfers:
60 J of energy every second
A 2000 W heater transfers:
2000 J every second
A higher power rating means energy is transferred at a greater rate.
Current, Voltage, and Power
The equation:
P = IV
shows that electrical power depends on both:
- current
- voltage
If voltage remains constant:
greater current → greater power
If current remains constant:
greater voltage → greater power
For example:
Current = 2 A
Voltage = 12 V
P = IV
P = 2 × 12
P = 24 W
The device transfers electrical energy at a rate of 24 J/s.
Worked Example: Simple Circuit
A lamp operates at:
V = 12 V
and draws:
I = 3 A
Calculate its power.
P = IV
P = 3 × 12
P = 36 W
The lamp transfers 36 J of energy each second.
Worked Example: Electric Motor
A motor operates at:
24 V
and draws:
5 A
Calculate the electrical power supplied to the motor.
P = IV
P = 5 × 24
P = 120 W
The motor receives electrical energy at a rate of:
120 J/s
Not all of this necessarily becomes useful mechanical power because the motor is not perfectly efficient.
Rearranging P = IV
Starting with:
P = IV
we can rearrange the equation.
To calculate current:
I = P/V
To calculate voltage:
V = P/I
So we have:
P = IV
I = P/V
V = P/I
Worked Example: Finding Current
An electrical heater has a power rating of:
1200 W
and operates at:
240 V
Calculate the current.
I = P/V
I = 1200/240
I = 5 A
Worked Example: Finding Voltage
A device operates at:
60 W
and draws:
2.5 A
Calculate the voltage.
V = P/I
V = 60/2.5
V = 24 V
Why P = IV?
Recall that voltage represents energy transferred per unit charge:
V = E/Q
Current represents charge flowing per unit time:
I = Q/t
Power is:
P = E/t
Since:
E = VQ
then:
P = VQ/t
But:
Q/t = I
Therefore:
P = IV
This connects electrical power directly to the movement of charge through a potential difference.
Power Ratings
Most electrical devices have a power rating.
The rating tells us the rate at which the device transfers energy when operating under its rated conditions.
For example:
| Device | Example Power |
|---|---|
| LED lamp | 10 W |
| Laptop | 60 W |
| Television | 100 W |
| Refrigerator | 150 W |
| Microwave oven | 1200 W |
| Hair dryer | 1500 W |
| Electric kettle | 2000 W |
These are illustrative values; actual devices vary considerably.
What Does a 2000 W Rating Mean?
Suppose a kettle is rated:
2000 W
This means that while operating at its rated power, it transfers energy at:
2000 J/s
In 1 second:
2000 J
In 10 seconds:
20,000 J
In 60 seconds:
120,000 J
Therefore, power tells us how quickly a device transfers energy.
Electrical Energy Consumption
Because:
P = E/t
we can rearrange:
E = Pt
This allows us to calculate the energy transferred by an electrical device.
where:
- E = energy (J)
- P = power (W)
- t = time (s)
Worked Example: Electric Heater
A 1500 W heater operates for 5 minutes.
First convert time:
5 min = 300 s
Then:
E = Pt
E = 1500 × 300
E = 450,000 J
or:
E = 450 kJ
Worked Example: Lamp
A 20 W lamp operates for 3 hours.
Convert time:
3 h = 10,800 s
Then:
E = Pt
E = 20 × 10,800
E = 216,000 J
or:
E = 216 kJ
Energy Depends on Power and Time
A device with a high power rating transfers energy quickly.
However, total energy consumption depends on both power and operating time.
Consider two devices.
Device A
Power = 2000 W
Time = 60 s
E = 2000 × 60
E = 120,000 J
Device B
Power = 100 W
Time = 3600 s
E = 100 × 3600
E = 360,000 J
Even though Device B has much lower power, it transfers more total energy because it operates for much longer.
Therefore:
high power does not automatically mean greater total energy consumption
Operating time matters.
Kilowatts
Household electrical devices are often rated in watts or kilowatts.
1 kW = 1000 W
Examples:
500 W = 0.5 kW
1500 W = 1.5 kW
2000 W = 2 kW
3500 W = 3.5 kW
Kilowatt-Hours
Electricity use in homes is commonly measured in kilowatt-hours (kWh) rather than joules.
A kilowatt-hour is a unit of energy, not power.
1 kWh is the energy transferred by a 1 kW device operating for 1 hour.
Therefore:
energy (kWh) = power (kW) × time
Understanding 1 kWh
Suppose a 1 kW heater operates for 1 hour.
Energy:
E = Pt
E = 1 kW × 1 h
E = 1 kWh
The same energy could be transferred by:
- a 2 kW device for 0.5 h
- a 0.5 kW device for 2 h
- a 0.25 kW device for 4 h
Each transfers:
1 kWh
Converting kWh to Joules
We know:
1 kW = 1000 W
and:
1 h = 3600 s
Therefore:
1 kWh = 1000 × 3600 J
1 kWh = 3,600,000 J
or:
1 kWh = 3.6 MJ
This is a useful conversion.
Worked Example: Kettle in kWh
A 2 kW kettle operates for 6 minutes.
Convert time to hours:
6 min = 0.1 h
Then:
E = Pt
E = 2 × 0.1
E = 0.2 kWh
In joules:
0.2 × 3.6 MJ = 0.72 MJ
or:
720,000 J
Worked Example: Air Conditioner
An air conditioner operates at an average electrical power of 1.5 kW for 8 hours.
Calculate its energy consumption.
E = Pt
E = 1.5 × 8
E = 12 kWh
The air conditioner uses 12 kWh of electrical energy over that period.
Electrical Energy Cost
If electricity costs a certain amount per kWh:
cost = energy used × price per kWh
For example, suppose a device uses:
5 kWh
and electricity costs:
$0.30 per kWh
Then:
cost = 5 × 0.30
cost = $1.50
This is why both power rating and operating time affect electricity bills.
Comparing Electrical Devices
Suppose two heaters operate for the same time.
Heater A:
1000 W
Heater B:
2000 W
Heater B transfers energy twice as quickly.
If both operate for 10 minutes:
Heater A:
E = 1000 × 600
E = 600,000 J
Heater B:
E = 2000 × 600
E = 1,200,000 J
The 2000 W heater transfers twice as much energy during the same period.
Higher Power Can Mean Shorter Operating Time
However, a higher-power appliance may complete a task more quickly.
Suppose two ideal heaters must transfer:
600,000 J
Heater A:
P = 1000 W
t = E/P
t = 600,000/1000
t = 600 s
Heater B:
P = 2000 W
t = 600,000/2000
t = 300 s
The more powerful heater completes the energy transfer in half the time.
This demonstrates why power and total energy consumption should not be confused.
Electrical Power in Heating Devices
Devices designed to produce heat often have relatively high power ratings.
Examples include:
- kettles
- ovens
- heaters
- toasters
- hair dryers
- irons
They need to transfer large amounts of thermal energy in relatively short periods.
Electrical Power in Motors
Electric motors transfer:
electrical energy → mechanical energy
Examples include motors in:
- fans
- elevators
- electric vehicles
- washing machines
- pumps
- power tools
A motor's electrical input power can be calculated using:
Pinput = IV
Its useful mechanical output power may be calculated using:
Poutput = W/t
or:
Poutput = Fv
The output is normally less than the input because real motors are not perfectly efficient.
Worked Example: Electric Motor
A motor operates at:
120 V
and draws:
10 A
Electrical input power:
P = IV
P = 10 × 120
P = 1200 W
Suppose its useful mechanical output power is:
960 W
Efficiency:
efficiency = useful output power / input power × 100
efficiency = 960/1200 × 100
efficiency = 80%
The remaining power is transferred mainly into thermal energy and sound.
Power in Simple Circuits
Suppose a resistor has:
V = 6 V
across it and:
I = 0.5 A
through it.
Power:
P = IV
P = 0.5 × 6
P = 3 W
The resistor transfers electrical energy at a rate of:
3 J/s
Much of this energy becomes thermal energy.
Electrical Power and Resistance
Using Ohm's law:
V = IR
we can combine this with:
P = IV
Substituting V = IR:
P = I × IR
Therefore:
P = I²R
Alternatively:
I = V/R
Substitute into P = IV:
P = V × V/R
Therefore:
P = V²/R
So three useful electrical power equations are:
P = IV
P = I²R
P = V²/R
For this topic, P = IV is the central equation, but the other forms can be useful when resistance is known.
Worked Example: Power and Resistance
A 10 Ω resistor carries a current of:
2 A
Use:
P = I²R
P = 2² × 10
P = 40 W
The resistor transfers electrical energy at a rate of 40 J/s.
Worked Example: Voltage and Resistance
A 12 Ω resistor is connected across:
24 V
Use:
P = V²/R
P = 24²/12
P = 576/12
P = 48 W
Power and Current in Household Devices
At a fixed supply voltage:
I = P/V
This means higher-power appliances generally draw larger currents.
For example, compare two devices operating at 230 V.
230 W Device
I = 230/230
I = 1 A
2300 W Device
I = 2300/230
I = 10 A
The higher-power device requires a much greater current.
This is one reason electrical wiring and protective devices must be appropriate for the current a circuit carries.
Power Ratings and Safe Operation
Electrical devices are designed to operate under particular electrical conditions.
A rating label may include:
- voltage
- current
- power
- frequency
- energy consumption information
For example, a label might indicate:
230 V
1500 W
This tells us that when operating as designed at the rated voltage, the appliance uses electrical power at approximately 1500 W.
Why Device Ratings Matter
Power ratings help users and engineers determine:
- how quickly a device transfers energy
- how much electrical energy it may consume
- how much current it may draw
- appropriate electrical connections
- likely operating costs
- energy-efficiency considerations
A power rating therefore provides important information about both performance and energy use.
Power and Efficiency
Electrical devices rarely convert all input energy into the desired output.
For example, an electric motor might receive:
1000 W electrical power
but provide:
850 W mechanical power
The remaining:
150 W
may be transferred into:
- thermal energy
- sound
- vibration
Efficiency:
efficiency = 850/1000 × 100
efficiency = 85%
Energy Flow Example
Consider a lamp receiving:
10 W electrical power
Suppose:
8 W → light
and:
2 W → thermal energy
Then:
10 W input = 8 W useful + 2 W other transfers
Energy is conserved.
Over 10 seconds:
Input energy:
E = Pt
E = 10 × 10
E = 100 J
Useful energy:
8 × 10 = 80 J
Thermal energy:
2 × 10 = 20 J
Therefore:
100 J = 80 J + 20 J
Choosing the Correct Equation
Use:
P = IV
when you know current and voltage.
Use:
P = E/t
when you know energy and time.
Use:
E = Pt
when you know power and operating time.
Use:
E(kWh) = P(kW) × t
when calculating household electricity consumption.
Use:
P = I²R
when current and resistance are known.
Use:
P = V²/R
when voltage and resistance are known.
Multi-Step Example
A heater operates at:
230 V
and draws:
8 A
It operates for:
15 minutes
Calculate Power
P = IV
P = 8 × 230
P = 1840 W
Convert Time
15 min = 900 s
Calculate Energy
E = Pt
E = 1840 × 900
E = 1,656,000 J
or:
E = 1.656 MJ
Alternatively:
P = 1.84 kW
t = 0.25 h
Therefore:
E = 1.84 × 0.25
E = 0.46 kWh
Both calculations describe the same energy transfer.
Common Mistakes
Confusing Power and Energy
Power is measured in:
watts
Energy is measured in:
joules or kilowatt-hours.
Thinking kWh Is a Unit of Power
It is not.
kW = power
kWh = energy
Forgetting Time Conversion
For joule calculations:
1 min = 60 s
1 h = 3600 s
For kWh calculations, time should normally be in hours.
Forgetting to Convert Watts to Kilowatts
For kWh:
1000 W = 1 kW
Therefore:
2500 W = 2.5 kW
Mixing Units
Do not calculate:
2000 W × 3 h
and call the answer joules.
Use compatible units:
W × s → J
or:
kW × h → kWh
Assuming High Power Always Means High Energy Consumption
A high-power device operating briefly may use less energy than a low-power device operating for many hours.
Confusing Current and Voltage
Current measures the rate of charge flow.
Voltage measures energy transferred per unit charge.
Power depends on both:
P = IV
Ignoring Efficiency
Electrical input power is not always equal to useful output power.
Real devices transfer some energy into other forms.
Check Your Understanding
- Define electrical power.
- State the SI unit of electrical power.
- What does a power of 1 W mean?
- State the equation relating power, current, and voltage.
- A device operates at 12 V and draws 4 A. Calculate its power.
- A motor operates at 24 V and draws 8 A. Calculate its electrical input power.
- A 1500 W heater operates at 250 V. Calculate the current.
- A 60 W device draws 2 A. Calculate its operating voltage.
- Explain what a 2000 W power rating means.
- A 500 W device operates for 20 s. Calculate the energy transferred.
- A 2 kW heater operates for 5 minutes. Calculate the energy transferred in joules.
- Calculate the answer to Question 11 in kWh.
- What is the difference between kW and kWh?
- Convert 1 kWh into joules.
- A 1.5 kW air conditioner operates for 6 h. Calculate its energy consumption in kWh.
- A 100 W device operates for 10 h. How much energy does it consume in kWh?
- Explain why a lower-power device can sometimes consume more energy than a higher-power device.
- A 10 Ω resistor carries 3 A. Calculate its power.
- A 20 Ω resistor has 40 V across it. Calculate its power.
- A motor receives 2000 W of electrical power and produces 1600 W of useful mechanical power. Calculate its efficiency.
- How much power is transferred into other forms in Question 20?
- A heater operates at 240 V and 10 A for 30 minutes. Calculate its power.
- Calculate the energy consumed by the heater in Question 22 in kWh.
- If electricity costs $0.30 per kWh, calculate the operating cost for Question 23.
- Explain why power ratings are useful when comparing electrical devices.
Key Terms
Electrical power — Rate at which electrical energy is transferred.
Power rating — Power a device is designed to use or transfer under specified operating conditions.
Watt (W) — SI unit of power; one joule per second.
Kilowatt (kW) — Unit of power equal to 1000 W.
Energy — Quantity that can be stored and transferred.
Joule (J) — SI unit of energy.
Kilowatt-hour (kWh) — Energy transferred by 1 kW of power operating for 1 hour.
Current (I) — Rate of flow of electric charge, measured in amperes.
Potential difference (V) — Energy transferred per unit charge, measured in volts.
Resistance (R) — Opposition to current in a circuit, measured in ohms.
Electrical energy — Energy transferred through electrical processes.
Input power — Rate at which energy enters a device.
Useful output power — Rate at which energy is transferred into the intended output.
Efficiency — Fraction of input power or energy transferred usefully.
Power consumption — Rate at which a device receives or transfers electrical energy.
Energy consumption — Total electrical energy transferred during a period of operation.
Key Takeaways
- Electrical power is the rate of electrical energy transfer.
- Electrical power is measured in watts.
- 1 W = 1 J/s.
- The main electrical power equation is P = IV.
- Power increases if current increases while voltage remains constant.
- Power increases if voltage increases while current remains constant.
- The equation can be rearranged to I = P/V and V = P/I.
- A device's power rating tells us how quickly it transfers energy under its rated conditions.
- Energy consumption depends on both power and operating time.
- Energy can be calculated using E = Pt.
- For household electricity calculations, E(kWh) = P(kW) × t
.
- kW is a unit of power, while kWh is a unit of energy.
- 1 kWh = 3.6 MJ.
- High-power appliances transfer energy rapidly, but they do not necessarily consume more total energy if they operate for shorter periods.
- Combining P = IV with Ohm's law gives P = I²R and P = V²/R.
- Higher-power devices generally draw greater current when operated at the same voltage.
- Electrical input power can be compared with useful output power to determine efficiency.
- Real electrical devices transfer some energy into unwanted forms, commonly thermal energy.
- Power ratings are useful for comparing device performance, estimating energy consumption, and understanding electrical requirements.
The central relationship is:
P = IV
and for energy consumption:
E = Pt
So remember:
power tells us how fast energy is transferred
while:
energy tells us how much has been transferred in total.
4. Efficiency
Learning outcomes
- I can explain why no real system is 100% efficient.
- I can distinguish between useful and wasted energy transfers.
- I can calculate efficiency using energy or power values.
- I can analyze the causes of energy dissipation in mechanical and electrical systems.
- I can compare the efficiencies of different devices and processes.
Efficiency
Efficiency describes how much of the energy transferred into a system becomes a useful energy output.
Whenever a machine or device operates, energy is transferred. However, not all of the input energy is transferred in the form we actually want.
For example:
- a motor transfers electrical energy into useful mechanical energy, but also becomes warm
- a lamp transfers electrical energy into light, but also transfers thermal energy to its surroundings
- a car engine transfers chemical energy into mechanical energy, but large amounts are transferred as thermal energy and sound
- a generator transfers mechanical energy into electrical energy, but some energy is dissipated through friction and heating
Real systems are therefore less than 100% efficient.
Useful and Wasted Energy Transfers
When analyzing efficiency, energy transfers can be divided into two broad categories.
Useful Energy
Useful energy is energy transferred in the form required for the intended purpose of the device.
Examples:
- mechanical energy from a motor
- light from a lamp
- thermal energy from a heater
- electrical energy from a generator
- kinetic energy from a vehicle engine
Wasted Energy
Wasted energy is energy transferred in forms that are not useful for the intended purpose.
Common examples include:
- unwanted thermal energy
- sound
- vibration
- deformation
"Wasted" does not mean that the energy has disappeared.
Energy is always conserved.
A better physical description is that the energy has been dissipated or transferred into less useful stores.
Energy Is Conserved
Consider a motor receiving:
1000 J
of electrical energy.
Suppose it produces:
800 J useful mechanical energy
and transfers:
200 J into thermal energy and sound
The energy balance is:
1000 J input = 800 J useful + 200 J wasted
Nothing has disappeared.
The total energy remains:
1000 J
Energy conservation still applies even though the motor is not 100% efficient.
Calculating Efficiency
Efficiency compares the useful output with the total input.

5. Energy Resources and Energy Density
Learning outcomes
- I can define energy density as the amount of energy stored per unit mass or volume.
- I can compare the energy densities of different fuels and energy storage systems.
- I can explain why energy density is important in transportation and energy production.
- I can evaluate the advantages and disadvantages of various energy resources using energy density data.
- I can analyze how energy density influences technological and environmental decisions.