Manipulating Algebraic Fractions

3. Multiplying and Dividing Algebraic Fractions

Learning outcomes
  • I can multiply algebraic fractions.
  • I can divide algebraic fractions using reciprocals.
  • I can simplify final answers.
  • I can factor before multiplying.
  • I can solve multi-step fraction problems.

Multiplying and Dividing Algebraic Fractions

Algebraic fractions can be multiplied and divided using the same basic rules as numerical fractions.

For multiplication:

a/b × c/d = ac/bd

For division, multiply by the reciprocal of the second fraction:

a/b ÷ c/d = a/b × d/c

The most efficient method is usually:

Restrict → Factor → Convert division → Cancel → Multiply → Simplify

Factoring before multiplying often prevents large, complicated expressions.

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10

Multiplying Numerical Fractions

Start with an ordinary fraction:

2/3 × 5/7

Multiply the numerators:

2 × 5 = 10

Multiply the denominators:

3 × 7 = 21

Therefore:

2/3 × 5/7 = 10/21

The same rule applies when variables are involved.


Multiplying Algebraic Fractions

Consider:

x/3 × 5/7

Multiply the numerators:

x × 5 = 5x

Multiply the denominators:

3 × 7 = 21

Therefore:

5x/21


Variables in Both Fractions

Multiply:

2x/5 × 3y/4

Numerator:

(2x)(3y) = 6xy

Denominator:

(5)(4) = 20

So:

6xy/20

Simplify:

3xy/10

Therefore:

2x/5 × 3y/4 = 3xy/10


Simplify Before Multiplying

Instead of multiplying first and simplifying afterward, it is often easier to cancel common factors first.

Consider:

4x/9 × 3/8x

Restrictions:

x ≠ 0

Factor the numbers:

4x/9 × 3/(8x)

Cancel x.

Simplify:

4/8 = 1/2

and:

3/9 = 1/3

Now multiply:

1/3 × 1/2 = 1/6

Therefore:

4x/9 × 3/(8x) = 1/6, where x ≠ 0


Why Cancelling First Helps

Suppose we multiply:

12x/35 × 14/9x

We could multiply first:

168x/(315x)

and then simplify.

But it is easier to simplify first.

Cancel x.

Simplify:

12/9 = 4/3

and:

14/35 = 2/5

Now:

4/5 × 2/3

Therefore:

8/15

Factoring and cancelling first keeps the numbers manageable.


Cancellation Works Across Multiplication

When fractions are multiplied, the entire expression is a product.

For example:

2x/3 × 9/(4x)

can be viewed as:

(2 × x × 9)/(3 × 4 × x)

Now common factors can be cancelled.

Cancel x:

(2 × 9)/(3 × 4)

Simplify:

2/4 = 1/2

9/3 = 3

Therefore:

3/2

with:

x ≠ 0


Cancel Factors, Not Terms

The same rule from simplifying algebraic fractions still applies.

You may cancel factors.

You may not cancel individual terms separated by addition or subtraction.

For example:

(x + 3)/x × x/5

Here x can cancel between the denominator of the first fraction and numerator of the second:

(x + 3)/5

But the x inside:

x + 3

cannot be cancelled.


Factor Before Multiplying

Consider:

(x² − 9)/(x + 2) × (x + 2)/(x − 3)

First factor:

x² − 9 = (x − 3)(x + 3)

So:

[(x − 3)(x + 3)]/(x + 2) × (x + 2)/(x − 3)

Cancel:

x + 2

and:

x − 3

Result:

x + 3

Restrictions from the original expression:

x ≠ −2

x ≠ 3

Therefore:

x + 3, where x ≠ −2, 3

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9

Restrictions Come from the Original Expression

Consider:

(x + 4)/(x − 2) × (x − 2)/(x + 1)

Cancel x − 2:

(x + 4)/(x + 1)

But the original denominators were:

x − 2

and:

x + 1

Therefore:

x ≠ 2

and:

x ≠ −1

The restriction x ≠ 2 remains even though x − 2 cancelled.


Multiplying Binomial Fractions

Multiply:

(x + 2)/(x + 5) × (x + 5)/(x + 7)

Restrictions:

x ≠ −5, −7

Cancel x + 5:

(x + 2)/(x + 7)

Therefore:

(x + 2)/(x + 7), where x ≠ −5, −7


Factoring Common Factors First

Multiply:

(2x + 6)/(x + 4) × (x + 4)/(4x)

Restrictions:

x ≠ −4, 0

Factor:

2(x + 3)/(x + 4) × (x + 4)/(4x)

Cancel x + 4.

Simplify 2/4:

1/2

Result:

(x + 3)/(2x)

Therefore:

(x + 3)/(2x), where x ≠ −4, 0


Factoring Trinomials Before Multiplying

Multiply:

(x² + 5x + 6)/(x + 4) × (x + 4)/(x + 2)

Factor:

x² + 5x + 6 = (x + 2)(x + 3)

So:

[(x + 2)(x + 3)]/(x + 4) × (x + 4)/(x + 2)

Cancel:

x + 4

and:

x + 2

Result:

x + 3

Restrictions:

x ≠ −4, −2


Multiplying Expressions with Powers

Multiply:

x²/6 × 9/x

Restriction:

x ≠ 0

Simplify:

x²/x = x

and:

9/6 = 3/2

Therefore:

3x/2

where:

x ≠ 0


Multiple Variables

Multiply:

3x²/4y × 8y²/9x

Restrictions:

x ≠ 0

y ≠ 0

Simplify:

3/9 = 1/3

8/4 = 2

x²/x = x

y²/y = y

Therefore:

2xy/3

with:

x ≠ 0, y ≠ 0


Dividing Fractions

To divide fractions, multiply by the reciprocal of the second fraction.

For numerical fractions:

2/3 ÷ 5/7

Flip the second fraction:

2/3 × 7/5

Multiply:

14/15

Therefore:

2/3 ÷ 5/7 = 14/15

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6

What Is a Reciprocal?

The reciprocal of a fraction is found by exchanging its numerator and denominator.

The reciprocal of:

3/5

is:

5/3

The reciprocal of:

x/7

is:

7/x

The reciprocal of:

(x + 2)/(x − 4)

is:

(x − 4)/(x + 2)

provided the required restrictions are satisfied.


Why Reciprocals Work

A number multiplied by its reciprocal equals 1.

For example:

3/5 × 5/3 = 1

Similarly:

x/4 × 4/x = 1

provided:

x ≠ 0

This is why division by a fraction can be rewritten as multiplication by its reciprocal.


Dividing Algebraic Fractions

Consider:

x/3 ÷ 2/5

Keep the first fraction:

x/3

Change division to multiplication:

×

Take the reciprocal of the second fraction:

5/2

So:

x/3 × 5/2

Multiply:

5x/6


A Useful Memory Aid

For division:

Keep → Change → Flip

Keep the first fraction.

Change ÷ to ×.

Flip the second fraction.

However, understanding the reciprocal rule is more important than simply memorizing the phrase.


Dividing with Variables

Simplify:

3x/4 ÷ 6x/5

Restrictions initially include:

x ≠ 0

Rewrite:

3x/4 × 5/(6x)

Cancel x.

Simplify 3/6:

1/2

Therefore:

5/8

with:

x ≠ 0


Dividing Binomial Fractions

Simplify:

(x + 2)/(x − 3) ÷ (x + 2)/(x + 5)

First rewrite using the reciprocal:

(x + 2)/(x − 3) × (x + 5)/(x + 2)

Cancel x + 2:

(x + 5)/(x − 3)

Now consider restrictions carefully.

From the original denominators:

x ≠ 3

x ≠ −5

But because we are dividing by:

(x + 2)/(x + 5)

the divisor itself cannot equal zero.

Therefore:

x + 2 ≠ 0

so:

x ≠ −2

Final result:

(x + 5)/(x − 3), where x ≠ 3, −5, −2


Division Has an Extra Restriction

This is important.

Consider:

A ÷ B

Not only must denominators be nonzero, but:

B ≠ 0

because division by zero is undefined.

For example:

5/x ÷ (x − 3)/(x + 2)

Restrictions from denominators:

x ≠ 0

x ≠ −2

The divisor must also not equal zero:

x − 3 ≠ 0

Therefore:

x ≠ 3

So the complete restrictions are:

x ≠ 0, −2, 3


A Complete Division Example

Simplify:

(x² − 9)/(x + 4) ÷ (x − 3)/(x + 2)

Restrictions from original denominators:

x ≠ −4

x ≠ −2

The divisor cannot equal zero:

x − 3 ≠ 0

so:

x ≠ 3

Now convert division to multiplication:

(x² − 9)/(x + 4) × (x + 2)/(x − 3)

Factor:

x² − 9 = (x − 3)(x + 3)

So:

(x − 3)(x + 3)/(x + 4) × (x + 2)/(x − 3)

Cancel x − 3:

(x + 3)(x + 2)/(x + 4)

Final answer:

(x + 3)(x + 2)/(x + 4)

where:

x ≠ −4, −2, 3


Never Flip the First Fraction

For:

a/b ÷ c/d

the correct conversion is:

a/b × d/c

Only the second fraction is replaced by its reciprocal.

Incorrect:

b/a × d/c

Do not flip both fractions.


Never Flip During Multiplication

If the operation is already multiplication:

a/b × c/d

do not take any reciprocal.

Simply factor, cancel common factors, and multiply.

Reciprocals are specifically used to convert division into multiplication.


Factoring Before Division

Simplify:

(x² − 4)/(x + 3) ÷ (x − 2)/(x + 5)

Restrictions:

x ≠ −3

x ≠ −5

The divisor cannot equal zero:

x ≠ 2

Convert:

(x² − 4)/(x + 3) × (x + 5)/(x − 2)

Factor:

x² − 4 = (x − 2)(x + 2)

So:

(x − 2)(x + 2)/(x + 3) × (x + 5)/(x − 2)

Cancel x − 2:

(x + 2)(x + 5)/(x + 3)

Therefore:

(x + 2)(x + 5)/(x + 3), where x ≠ −3, −5, 2


Factoring Both Fractions

Simplify:

(x² + 5x + 6)/(x² − 9) × (x − 3)/(x + 2)

Factor:

x² + 5x + 6 = (x + 2)(x + 3)

x² − 9 = (x − 3)(x + 3)

So:

(x + 2)(x + 3)/[(x − 3)(x + 3)] × (x − 3)/(x + 2)

Cancel:

x + 2

x + 3

x − 3

Result:

1

Restrictions from the original denominators:

x ≠ 3, −3, −2

Therefore:

1, where x ≠ −3, −2, 3

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8

Multi-Step Fraction Problems

Some expressions contain several multiplication and division operations.

For example:

x/3 × 6/(x + 2) ÷ 2x/(x + 2)

Work systematically.

First convert division to multiplication:

x/3 × 6/(x + 2) × (x + 2)/(2x)

Now cancel common factors:

  • x cancels
  • x + 2 cancels
  • 6/(3 × 2) = 1

Therefore:

1

Restrictions include:

x ≠ 0

x ≠ −2

The divisor:

2x/(x + 2)

must also not equal zero, which again requires:

x ≠ 0


Multiple Division Operations

Consider:

a/b ÷ c/d ÷ e/f

Division is performed from left to right.

First:

a/b ÷ c/d = a/b × d/c

Then divide the result by e/f:

a/b × d/c × f/e

So:

adf/bce

assuming all required quantities are nonzero.

Do not simply flip every fraction without considering the operations.


Fractions Containing Constants

Simplify:

5x/12 × 18/(10x)

Restriction:

x ≠ 0

Simplify:

5/10 = 1/2

18/12 = 3/2

Cancel x.

Therefore:

3/4


Fractions with Negative Signs

Consider:

−2x/5 × 15/(4x)

Restriction:

x ≠ 0

Cancel x.

Simplify:

15/5 = 3

and:

−2/4 = −1/2

Therefore:

−3/2


Negative Signs Can Be Written in Different Places

These are equivalent:

−a/b

(−a)/b

a/(−b)

But:

(−a)/(−b) = a/b

Two negative factors produce a positive result.


Reversed Factors

Consider:

(x − 4)/(x + 2) × (x + 2)/(4 − x)

Notice:

4 − x = −(x − 4)

So:

(x − 4)/(x + 2) × (x + 2)/[−(x − 4)]

Cancel:

x + 2

and:

x − 4

Result:

−1

Restrictions:

x ≠ −2, 4


Complex Fractions

A complex fraction is a fraction containing another fraction.

For example:

(x/3)/(2/5)

This means:

x/3 ÷ 2/5

Convert:

x/3 × 5/2

Therefore:

5x/6

Complex fractions can often be handled by rewriting the large fraction bar as division.


Another Complex Fraction

Consider:

[(x + 2)/4]/[(x − 1)/6]

Rewrite:

(x + 2)/4 ÷ (x − 1)/6

Multiply by the reciprocal:

(x + 2)/4 × 6/(x − 1)

Simplify:

6/4 = 3/2

Therefore:

3(x + 2)/[2(x − 1)]

Restrictions:

x ≠ 1

The divisor must also be nonzero:

x +?

Here the divisor is:

(x − 1)/6

which is zero when x = 1, already excluded.


A Multi-Step Factoring Example

Simplify:

(x² − 16)/(x² + 7x + 12) × (x + 3)/(x − 4)

Factor:

x² − 16 = (x − 4)(x + 4)

x² + 7x + 12 = (x + 3)(x + 4)

So:

(x − 4)(x + 4)/[(x + 3)(x + 4)] × (x + 3)/(x − 4)

Cancel all common factors:

1

Restrictions:

From:

(x + 3)(x + 4)

we get:

x ≠ −3, −4

From:

x − 4

we get:

x ≠ 4

Therefore:

1, where x ≠ −4, −3, 4


A Multi-Step Division Example

Simplify:

(x² − 25)/(x² + 3x − 10) ÷ (x + 5)/(x − 2)

Factor the first denominator:

x² + 3x − 10 = (x + 5)(x − 2)

Restrictions from denominators:

x ≠ −5, 2

The divisor:

(x + 5)/(x − 2)

cannot equal zero, so:

x ≠ −5

Now convert division:

(x² − 25)/[(x + 5)(x − 2)] × (x − 2)/(x + 5)

Factor:

x² − 25 = (x − 5)(x + 5)

Then:

(x − 5)(x + 5)/[(x + 5)(x − 2)] × (x − 2)/(x + 5)

Cancel x − 2.

Cancel one x + 5.

Result:

(x − 5)/(x + 5)

Therefore:

(x − 5)/(x + 5), where x ≠ −5, 2


Verifying by Substitution

Suppose:

(x² − 9)/(x + 2) × (x + 2)/(x − 3)

simplifies to:

x + 3

with:

x ≠ −2, 3

Choose an allowed value:

x = 5

Original:

(25 − 9)/7 × 7/2

= 16/7 × 7/2

= 8

Simplified:

5 + 3 = 8

The results agree.


Verification Can Catch Cancellation Errors

Suppose someone claims:

(x + 4)/x × 2/3 = 8/3

by cancelling x incorrectly.

Choose:

x = 2

Original:

(2 + 4)/2 × 2/3

= 6/2 × 2/3

= 3 × 2/3

= 2

Claimed answer:

8/3

Since:

2 ≠ 8/3

the simplification is incorrect.


When an Answer Cannot Be Simplified Further

Consider:

(x + 3)/(x + 5) × (x + 7)/(x + 2)

There are no common factors between numerators and denominators.

Therefore:

(x + 3)(x + 7)/[(x + 5)(x + 2)]

is already simplified.

It is usually best to leave it in factored form.


Factored Form Is Often Best

When working with algebraic fractions, factored form makes restrictions and common factors easier to see.

For example:

(x − 3)(x + 2)/[(x + 5)(x − 7)]

is often more useful than expanding everything.

Factored form helps us see immediately that the restrictions are:

x ≠ −5, 7

and whether any common factors can be cancelled.


Algebraic Fractions in Science

Multiplication and division of algebraic fractions appear in scientific formulas.

For example:

v = d/t

and:

t = d/v

Suppose another relationship gives:

d = Pt/F

Substituting this into the speed equation gives:

v = (Pt/F)/t

This can be viewed as:

v = Pt/(Ft)

Cancel t:

v = P/F

where the relevant denominators must be nonzero.

Algebraic fraction skills therefore become increasingly useful when formulas are combined.


Solving Practical Problems

Suppose fuel efficiency is modeled by:

E = d/f

where:

  • E = distance traveled per unit of fuel
  • d = distance
  • f = fuel used

If another relationship gives:

d = vt

then substitute:

E = vt/f

If:

v = 80 km/h

t = 4 h

f = 25 L

then:

E = (80)(4)/25

E = 320/25

Therefore:

E = 12.8 km/L

This combines substitution, multiplication, and division.


Common Mistakes

Mistake: Adding numerators or denominators when multiplying.

Incorrect:

a/b × c/d = (a + c)/(b + d)

Correct:

a/b × c/d = ac/bd


Mistake: Flipping the second fraction during multiplication.

Reciprocals are used for division, not ordinary multiplication.


Mistake: Flipping the first fraction during division.

For:

a/b ÷ c/d

only the second fraction is replaced by its reciprocal.


Mistake: Forgetting to change ÷ to ×.

The reciprocal rule requires:

÷ → × reciprocal


Mistake: Cancelling terms instead of factors.

You cannot cancel x from:

(x + 3)/x


Mistake: Multiplying before factoring.

This often creates unnecessarily complicated expressions.

Factor first whenever possible.


Mistake: Forgetting restrictions.

Cancelled factors still produce restrictions if they appeared in an original denominator.


Mistake: Forgetting that a divisor cannot equal zero.

When dividing by an algebraic fraction, the entire divisor must be nonzero.


Mistake: Expanding the final answer unnecessarily.

Factored form is often simpler and clearer.


Mistake: Cancelling factors before division has been converted to multiplication.

First replace division with multiplication by the reciprocal. Then cancel.


Key Terms

Algebraic fraction — fraction containing variables or algebraic expressions.

Numerator — expression above the fraction line.

Denominator — expression below the fraction line.

Factor — quantity multiplied by another quantity.

Common factor — factor shared between numerator and denominator.

Factorization — rewriting an expression as a product of factors.

Cancel — divide numerator and denominator by the same nonzero factor.

Reciprocal — fraction formed by exchanging numerator and denominator.

Restriction — value excluded because it makes an original denominator zero or otherwise makes an operation undefined.

Product — result of multiplication.

Quotient — result of division.

Complex fraction — fraction containing one or more fractions within its numerator or denominator.

Difference of squares — factoring pattern a² − b² = (a − b)(a + b).

Equivalent expression — expression with the same value over its permitted domain.

Verification — process of checking that a result is mathematically equivalent to the original.


Key Takeaways

  • Algebraic fractions multiply using the same basic rule as numerical fractions.
  • Multiply numerator by numerator and denominator by denominator.
  • Factor expressions before multiplying whenever possible.
  • Cancelling before multiplication often makes calculations much easier.
  • Only common factors can be cancelled.
  • Terms separated by addition or subtraction cannot simply be cancelled.
  • When dividing fractions, multiply by the reciprocal of the second fraction.
  • A useful memory aid is Keep → Change → Flip.
  • Only the divisor is replaced by its reciprocal.
  • Do not use reciprocals when the operation is already multiplication.
  • Factor after converting division to multiplication so common factors are visible.
  • Difference-of-squares and trinomial factoring can reveal common factors.
  • Restrictions from original denominators must be retained.
  • Division introduces an additional requirement: the entire divisor cannot equal zero.
  • Cancelled factors can still create restrictions.
  • Factored form is often the clearest final form.
  • Multi-step problems should be handled systematically rather than trying to perform every operation at once.
  • Complex fractions can be interpreted as division problems.
  • Negative signs must be handled carefully.
  • Reversed factors such as x − a and a − x differ by a factor of −1.
  • Substitution can be used to verify simplified answers.
  • Multiplying and dividing algebraic fractions is important for later work with rational equations, functions, formulas, rates, and scientific relationships.

Check Your Understanding

  1. Multiply and simplify 2x/3 × 5/4.
  2. Multiply and simplify 3x/5 × 10/9x and state the restriction.
  3. Multiply and simplify 4x²/7 × 14/8x.
  4. Multiply and simplify 3x²/4y × 8y²/9x and state all restrictions.
  5. Simplify (x + 2)/(x + 5) × (x + 5)/(x + 7).
  6. Simplify (x² − 9)/(x + 4) × (x + 4)/(x − 3) and state all restrictions.
  7. Simplify (x² + 5x + 6)/(x + 4) × (x + 4)/(x + 2).
  8. Explain why factoring before multiplying algebraic fractions is often useful.
  9. Find the reciprocal of 3x/5.
  10. Find the reciprocal of (x + 2)/(x − 4).
  11. Simplify x/4 ÷ 3/5.
  12. Simplify 3x/7 ÷ 6x/5 and state the restriction.
  13. Simplify (x + 3)/(x − 2) ÷ (x + 3)/(x + 5) and state all restrictions.
  14. Simplify (x² − 16)/(x + 1) ÷ (x − 4)/(x + 3) and state all restrictions.
  15. Explain why the fraction you are dividing by cannot equal zero.
  16. Explain why x cannot be cancelled from (x + 5)/x.
  17. Simplify (x − 6)/(x + 2) × (x + 2)/(6 − x).
  18. Simplify [(x + 4)/5]/[(x − 2)/10] and state all restrictions.
  19. Use substitution to explain how you could verify a simplified algebraic fraction.
  20. Simplify completely:

(x² − 25)/(x² + 2x − 15) ÷ (x + 5)/(x − 3)

State all restrictions and explain each step.