Resonance and Sound Waves

4. Beats and Interference

Learning outcomes
  • I can explain constructive and destructive interference using the principle of superposition.
  • I can describe how beats are formed when two waves with slightly different frequencies interfere.
  • I can calculate beat frequency from the frequencies of interfering sound waves.
  • I can explain how musicians use beats to tune musical instruments accurately.
  • I can analyze real-world examples of sound interference and describe their effects on wave amplitude and sound intensity.

Beats and Interference

When two or more waves meet, they combine according to the principle of superposition. The resulting displacement at any point is the sum of the individual wave displacements at that point.

This interaction is called interference.

Interference can make a wave temporarily larger, smaller, or even cancel it completely. In sound waves, interference affects the pressure variations reaching our ears, changing the amplitude and therefore the perceived loudness or sound intensity.

A particularly interesting form of sound interference occurs when two sounds have slightly different frequencies. Their interference produces regular changes in loudness called beats.

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7

The Principle of Superposition

The principle of superposition states:

When two or more waves overlap, the resultant displacement is the algebraic sum of the individual displacements.

For two waves:

y_resultant = y₁ + y₂

This means that waves do not normally destroy one another permanently when they overlap.

Instead:

  1. the waves meet
  2. their displacements combine
  3. interference occurs
  4. the waves continue travelling afterward

The effect depends strongly on the relative phase of the waves.


Constructive Interference

Constructive interference occurs when waves overlap so that their displacements reinforce each other.

For example, if two crests arrive at the same place at the same time:

positive displacement + positive displacement = larger positive displacement

Similarly:

trough + trough = deeper trough

For two identical waves of amplitude A that are perfectly in phase:

resultant amplitude = 2A

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7

Waves in Phase

Two waves are in phase when corresponding parts of the waves occur together.

For example:

  • crest meets crest
  • trough meets trough
  • compression meets compression
  • rarefaction meets rarefaction

For two identical sinusoidal waves, a phase difference of:

0°

produces maximum constructive interference.

A phase difference of:

360°

also represents the same relative phase after one complete cycle.


Destructive Interference

Destructive interference occurs when overlapping waves have displacements in opposite directions.

For example:

positive displacement + negative displacement = smaller resultant displacement

If two waves have equal amplitudes and are exactly opposite in phase:

resultant amplitude = 0

This is called complete destructive interference.

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Waves Out of Phase

Two identical sinusoidal waves are completely out of phase when their phase difference is:

180°

Then:

  • crest meets trough
  • trough meets crest

If their amplitudes are equal, complete cancellation occurs at that location.

If the amplitudes are different, cancellation is only partial.

For example:

Wave 1 amplitude = 5 units

Wave 2 amplitude = 3 units in the opposite direction

Resultant amplitude:

5 − 3 = 2 units


Constructive and Destructive Interference Compared

Constructive Interference Destructive Interference
Waves reinforce Waves oppose
Resultant amplitude increases Resultant amplitude decreases
Crest meets crest Crest meets trough
Identical waves: phase difference 0° Identical waves: phase difference 180°
Can produce greater sound intensity Can produce lower sound intensity

Interference can also occur anywhere between these two extremes.


Interference of Sound Waves

Sound is a longitudinal wave involving variations in pressure.

When two sound waves reach the same location, their pressure variations combine.

Constructive interference can produce larger pressure variations.

Destructive interference can produce smaller pressure variations.

As a result, interference can create locations where sound is:

  • louder
  • quieter
  • nearly cancelled

Amplitude and Sound Intensity

The intensity of a wave is related to the square of its amplitude:

I ∝ A²

where:

  • I = intensity
  • A = amplitude

This means changes in amplitude can produce much larger changes in intensity.

If the amplitude doubles:

I_new/I_old = (2A)²/A²

I_new = 4I_old

So doubling wave amplitude corresponds to four times the intensity, assuming the waves are otherwise comparable.


Worked Example: Constructive Interference

Two identical coherent sound waves each have amplitude:

A = 2.0 units

They arrive perfectly in phase.

Resultant amplitude:

A_resultant = 2.0 + 2.0

A_resultant = 4.0 units

Compared with one wave, the amplitude has doubled.

Since:

I ∝ A²

the intensity at perfect constructive interference is:

4 times the intensity of either individual wave


Worked Example: Destructive Interference

Two waves have amplitudes:

A₁ = 6 units

A₂ = 4 units

They arrive exactly opposite in phase.

Resultant amplitude magnitude:

A_resultant = |6 − 4|

A_resultant = 2 units

The waves partially cancel.

Complete cancellation would require equal amplitudes as well as the correct phase relationship.


Path Difference and Interference

Interference also depends on how far each wave travels before reaching a particular point.

The difference between the two travel distances is called the path difference.

For two coherent waves, constructive interference occurs when the path difference is:

Δd = nλ

where:

n = 0, 1, 2, 3, ...

Examples include:

0, λ, 2λ, 3λ ...


Destructive Interference and Path Difference

For two coherent waves initially in phase, destructive interference occurs when:

Δd = (n + ½)λ

Examples include:

λ/2, 3λ/2, 5λ/2 ...

The extra half-wavelength causes the waves to arrive out of phase.

This explains why sound can be louder at some locations and quieter at others.


Interference Patterns in Rooms

Sound waves can reach a listener by different paths.

For example, sound may travel:

  • directly from a speaker
  • after reflecting from a wall
  • after reflecting from the floor
  • after reflecting from the ceiling

The waves can then interfere.

At some locations:

constructive interference → greater amplitude

At other locations:

destructive interference → smaller amplitude

This can create uneven sound levels around a room.


What Are Beats?

Beats are regular variations in sound amplitude produced when two sound waves with slightly different frequencies interfere.

Suppose one source produces:

440 Hz

and another produces:

442 Hz

The waves repeatedly move:

in phase → out of phase → in phase → out of phase

The listener hears:

loud → quiet → loud → quiet

This repeating variation in loudness is the beat pattern.

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8

Why Beats Form

Consider two waves that begin in phase.

At first:

crest + crest → constructive interference

The sound is relatively loud.

Because the frequencies are slightly different, one wave gradually moves ahead of the other.

Eventually:

crest + trough → destructive interference

The sound becomes relatively quiet.

The faster wave continues gaining phase.

Eventually the waves become aligned again:

crest + crest → constructive interference

The sound becomes loud again.

This cycle repeats.


Beat Frequency

The number of loudness cycles heard each second is called the beat frequency.

For two frequencies f₁ and f₂:

f_beat = |f₁ − f₂|

The absolute value is used because beat frequency is positive.


Worked Example: Beat Frequency

Two tuning forks have frequencies:

f₁ = 440 Hz

f₂ = 444 Hz

Beat frequency:

f_beat = |444 − 440|

f_beat = 4 Hz

The listener hears approximately:

4 beats per second


Worked Example: Close Frequencies

Two speakers produce:

f₁ = 512 Hz

f₂ = 515 Hz

Then:

f_beat = |515 − 512|

f_beat = 3 Hz

The loudness rises and falls three times each second.


Finding an Unknown Frequency

Beat frequency can also be used to determine an unknown frequency.

Suppose a known tuning fork produces:

440 Hz

An unknown source produces:

5 beats per second

Then:

|f_unknown − 440| = 5

Therefore:

f_unknown = 435 Hz

or:

f_unknown = 445 Hz

Beat frequency alone does not tell us whether the unknown frequency is above or below the known frequency.

Additional information is needed.


Resolving the Two Possible Frequencies

Suppose the unknown frequency produces 5 beats per second with a 440 Hz reference.

Possible frequencies are:

435 Hz or 445 Hz

Now suppose the unknown source is adjusted slightly upward in frequency.

If the beat frequency becomes smaller, the unknown frequency was probably below 440 Hz and is moving toward it.

If the beat frequency becomes larger, it may have been above 440 Hz and is moving farther away.

This principle is extremely useful when tuning musical instruments.


Beats and Musical Tuning

Musicians can use beats to compare the frequency of an instrument with a known reference frequency.

Suppose a tuning reference produces:

440 Hz

A string being tuned produces:

443 Hz

Beat frequency:

f_beat = |443 − 440|

f_beat = 3 Hz

The musician hears three beats each second.

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8

Tuning by Reducing Beat Frequency

The musician adjusts the instrument.

Suppose the frequencies change:

443 Hz → 442 Hz → 441 Hz → 440 Hz

The beat frequencies become:

3 Hz → 2 Hz → 1 Hz → 0 Hz

As the instrument approaches the reference frequency, the beats become slower.

When the frequencies match:

f_beat = |440 − 440| = 0 Hz

The beats disappear.

This tells the musician that the frequencies match closely.


Why Beats Are Useful for Tuning

The human ear may have difficulty deciding whether one sustained tone is slightly higher or lower than another.

However, slow changes in loudness can be easy to detect.

Beats therefore transform a small frequency difference into a noticeable rhythm in amplitude.

The closer the two frequencies become:

smaller frequency difference → slower beats

When they match:

frequency difference = 0 → no beats


Tuning a Guitar

Suppose a reference tone is:

330 Hz

A guitar string produces:

326 Hz

Beat frequency:

f_beat = |330 − 326|

f_beat = 4 Hz

The guitarist tightens the string, raising its frequency.

At 328 Hz:

f_beat = 2 Hz

At 329.5 Hz:

f_beat = 0.5 Hz

At 330 Hz:

f_beat = 0 Hz

The disappearing beats indicate that the frequencies have matched.


Tuning Pianos

Beat patterns are also important in piano tuning.

A piano tuner can compare:

  • strings with reference frequencies
  • different strings producing related pitches
  • intervals between notes

The rate of beating provides information about small differences in frequency.

In practical musical tuning, some intervals are intentionally adjusted according to the tuning system being used, so not every useful tuning comparison necessarily aims for zero beats.


The Beat Envelope

When two similar frequencies interfere, the resulting waveform has a rapidly oscillating wave whose amplitude slowly rises and falls.

The outer shape showing the amplitude variation is called the envelope.

The envelope corresponds to the pattern of:

loud → quiet → loud → quiet

The beat frequency describes how often the loudness maxima repeat.


Mathematical Description of Beats

Suppose two equal-amplitude waves are:

y₁ = A cos(2πf₁t)

and:

y₂ = A cos(2πf₂t)

Using superposition:

y = y₁ + y₂

The combination can be expressed as:

y = 2A cos[π(f₁ − f₂)t] cos[π(f₁ + f₂)t]

This shows two important features.

The rapidly changing part corresponds approximately to the average frequency:

f_average = (f₁ + f₂)/2

The slowly changing amplitude produces the beats.

The audible beat frequency is:

f_beat = |f₁ − f₂|


Average Frequency Example

Suppose:

f₁ = 500 Hz

f₂ = 506 Hz

Average frequency:

f_average = (500 + 506)/2

f_average = 503 Hz

Beat frequency:

f_beat = |506 − 500|

f_beat = 6 Hz

The listener therefore hears a tone near 503 Hz whose loudness varies about six times each second.


Beat Period

The time between successive loudness maxima is the beat period.

Since:

T = 1/f

the beat period is:

T_beat = 1/f_beat

For a beat frequency of 4 Hz:

T_beat = 1/4

T_beat = 0.25 s

A loudness maximum occurs approximately every 0.25 seconds.


Worked Example: Beat Period

Two sources produce:

f₁ = 300 Hz

f₂ = 302.5 Hz

Beat frequency:

f_beat = |302.5 − 300|

f_beat = 2.5 Hz

Beat period:

T_beat = 1/2.5

T_beat = 0.40 s

The sound reaches a loudness maximum approximately every 0.40 seconds.


Beats Require Similar Frequencies

The classic beat effect is most easily heard when the two frequencies are relatively close together.

If the frequency difference becomes large, the ear may begin to distinguish two separate tones rather than hearing a clear slow beat pattern.

Therefore, beats are particularly useful for detecting small frequency differences.


Coherence and Stable Interference

For a stable interference pattern, waves should have a predictable phase relationship.

Such waves are described as coherent.

Two independent sound sources may not maintain perfect coherence for long periods.

However, waves derived from related or stable sources can produce clear interference effects.

Beat formation does not require the frequencies to be identical; in fact, the small frequency difference is what produces the changing phase relationship.


Sound Interference in Speakers

Suppose two speakers produce the same frequency.

At one location, the sound waves may arrive in phase.

The listener experiences constructive interference.

At another location, the path difference may cause the waves to arrive out of phase.

The listener experiences destructive interference.

As a person moves around the room, the sound intensity may therefore change.

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7

Noise-Cancelling Headphones

Active noise cancellation uses destructive interference.

A microphone detects unwanted sound.

Electronics produce another sound wave designed to oppose it.

Ideally:

noise wave + opposing wave → reduced resultant amplitude

The unwanted sound becomes quieter.

This is sometimes described as producing anti-noise.


Why Noise Cancellation Is Not Perfect

Perfect cancellation would require the cancelling wave to have exactly the correct:

  • frequency
  • amplitude
  • phase
  • timing

at the listener's ear.

Real environments contain complicated sounds arriving from many directions.

Therefore, noise cancellation usually reduces unwanted sound rather than eliminating every sound completely.

It tends to be especially effective for predictable, lower-frequency background noise.


Interference in Concert Halls

Sound interference is an important consideration in the design of:

  • concert halls
  • theatres
  • classrooms
  • recording studios
  • stadiums

Reflected sound waves can interfere with direct sound.

Poor design can produce areas where certain frequencies become:

  • unusually loud
  • unusually quiet
  • unclear

Acoustic design attempts to control these effects.


Multiple Speakers

Large venues often use many speakers.

If their sound arrives at different times or phases, interference can reduce sound quality.

Engineers therefore consider:

  • speaker position
  • distance
  • timing
  • phase
  • frequency response
  • reflections

Digital systems can introduce carefully controlled delays to coordinate sound arriving from different speakers.


Interference and Standing Waves

Reflected waves can interfere with incoming waves.

Under suitable conditions, this produces standing waves.

Standing waves contain:

  • nodes
  • antinodes

At a node, the wave amplitude is very small.

At an antinode, the amplitude is large.

Standing waves in rooms can therefore make certain frequencies noticeably louder or quieter at different locations.


Interference in Musical Instruments

Musical instruments depend on wave interference.

Reflections inside:

  • strings
  • pipes
  • air columns

can produce standing waves.

Constructive interference reinforces frequencies that satisfy the instrument's resonance conditions.

This helps determine the frequencies that the instrument can produce strongly.


Sound Intensity and Distance

Interference should not be confused with the normal decrease in intensity as sound spreads.

A sound can become quieter because:

  • energy spreads over a larger area
  • energy is absorbed
  • destructive interference occurs

These are different physical processes.

When analyzing a sound situation, it is important to identify which mechanism is responsible.


Real-World Example: Aircraft Cabins

Aircraft cabins contain relatively steady low-frequency noise from:

  • engines
  • airflow
  • mechanical systems

Active noise-cancelling headphones can analyze this noise and generate an opposing waveform.

Destructive interference reduces the pressure variations reaching the listener.

The result is a quieter perceived environment.


Real-World Example: Vehicle Noise Control

Active noise-control systems can also be used in vehicles.

Microphones detect unwanted sound.

Speakers generate controlled sound waves.

The waves interfere destructively with selected noise frequencies.

The system must continuously adjust because vehicle conditions change with:

  • speed
  • engine operation
  • road surface
  • passenger position

Real-World Example: Speaker Placement

Imagine two speakers producing the same 600 Hz tone.

A listener at one position may receive both waves in phase.

The sound is relatively loud.

A second listener may be positioned where one wave travels an additional half-wavelength.

The waves can arrive approximately 180° out of phase.

The second listener may hear a much quieter sound.

This demonstrates that interference depends on location.


Worked Example: Wavelength and Destructive Interference

Suppose sound has:

f = 680 Hz

and the speed of sound is:

v = 340 m/s

Using:

v = fλ

Wavelength:

λ = v/f

λ = 340/680

λ = 0.50 m

For the first destructive interference condition:

Δd = λ/2

Δd = 0.50/2

Δd = 0.25 m

A path difference of 0.25 m can therefore produce destructive interference if the waves began in phase.


Worked Example: Constructive Interference

Using the same wavelength:

λ = 0.50 m

Constructive interference can occur for:

Δd = nλ

Possible path differences include:

0 m, 0.50 m, 1.00 m, 1.50 m ...

At these positions, the waves can arrive in phase.


Moving Through an Interference Pattern

Imagine walking through a room while two coherent speakers produce the same tone.

As your position changes:

  • path difference changes
  • phase difference changes
  • interference changes

You might hear:

loud → quiet → loud → quiet

This is an interference pattern caused by position.

It should not be confused with beats, which result from waves having slightly different frequencies.


Beats vs Spatial Interference

These two effects can sound superficially similar but have different causes.

Beats Spatial Interference
Usually slightly different frequencies Can use the same frequency
Loudness changes with time Loudness changes with position
Relative phase continually changes Phase difference depends on path difference
Beat rate = frequency difference Pattern spacing depends on wavelength and geometry

This distinction is important.


Interference Does Not Destroy Energy

When destructive interference produces a low-amplitude region, the energy has not simply disappeared.

Interference changes how wave energy is distributed through space.

In a larger wave system, regions of destructive interference are associated with energy being redistributed elsewhere.

This is another example of conservation of energy.


Interference in Other Waves

Interference is not limited to sound.

The principle of superposition applies to many types of waves, including:

  • water waves
  • electromagnetic waves
  • light
  • radio waves
  • microwaves

The details differ, but constructive and destructive interference remain fundamental wave behaviours.


A Complete Beat Problem

Two sound sources produce:

f₁ = 438 Hz

f₂ = 442 Hz

Beat frequency:

f_beat = |442 − 438|

f_beat = 4 Hz

Average frequency:

f_average = (442 + 438)/2

f_average = 880/2

f_average = 440 Hz

Beat period:

T_beat = 1/4

T_beat = 0.25 s

Therefore, the listener hears a tone near 440 Hz whose amplitude rises and falls four times each second.


A Tuning Problem

A piano string is compared with a:

440 Hz

reference tone.

Initially, the musician hears:

6 beats per second

Possible string frequencies are:

434 Hz or 446 Hz

The musician slightly increases the string frequency.

The beat frequency falls to:

4 Hz

This indicates that the string is moving toward 440 Hz.

Therefore, the original string frequency was:

434 Hz

After adjustment:

436 Hz

would produce 4 beats per second.

The musician continues increasing the frequency until the beats disappear at approximately:

440 Hz


Common Mistakes

Thinking interference permanently changes the original waves

The waves superpose while overlapping and then continue propagating.

Thinking constructive interference means two waves have the same frequency

Constructive interference describes how their displacements combine at a particular place and time.

Thinking destructive interference always produces zero amplitude

Complete cancellation requires appropriate phase and equal amplitudes.

Confusing beats with ordinary interference patterns

Beats are produced by slightly different frequencies and create a time-varying amplitude.

Adding frequencies to find beat frequency

Beat frequency is the absolute difference:

f_beat = |f₁ − f₂|

Using the average frequency as the beat frequency

The average frequency describes the approximate pitch of the rapidly oscillating sound, not the beat rate.

Thinking zero beats means there is no sound

Zero beats means the frequencies match. The sound itself can still be strong.

Assuming a beat frequency identifies an unknown frequency uniquely

An unknown frequency may be either above or below the reference frequency.

Thinking destructive interference violates conservation of energy

Interference redistributes wave energy rather than destroying it.


Key Terms

Superposition — principle stating that overlapping wave displacements add algebraically.

Interference — combination of overlapping waves according to superposition.

Constructive interference — interference in which wave displacements reinforce one another.

Destructive interference — interference in which wave displacements oppose one another.

Phase — position of a point within a wave cycle relative to another wave or reference.

In phase — waves having corresponding parts of their cycles aligned.

Out of phase — waves having different positions within their cycles.

Path difference — difference between distances travelled by two waves to reach a point.

Coherent waves — waves maintaining a predictable phase relationship.

Beat — periodic variation in amplitude caused by interference between waves with slightly different frequencies.

Beat frequency — number of amplitude or loudness cycles per second, equal to the absolute difference between the two frequencies.

Beat period — time between successive beat maxima.

Envelope — slowly varying outline of the amplitude of a beat waveform.

Sound intensity — rate of sound energy transfer per unit area.

Active noise cancellation — use of controlled destructive interference to reduce unwanted sound.


Key Takeaways

  • The principle of superposition states that overlapping wave displacements add algebraically.
  • Constructive interference occurs when wave displacements reinforce each other.
  • Destructive interference occurs when wave displacements oppose each other.
  • Equal waves perfectly in phase can produce twice the individual amplitude.
  • Equal waves 180° out of phase can completely cancel at a particular location.
  • Wave intensity is proportional to amplitude squared.
  • Path difference determines whether coherent waves arrive in or out of phase.
  • For initially in-phase coherent waves, constructive interference occurs when Δd = nλ.
  • Destructive interference occurs when Δd = (n + ½)λ.
  • Beats result from interference between waves with slightly different frequencies.
  • The changing phase relationship causes alternating constructive and destructive interference.
  • Beat frequency is calculated using f_beat = |f₁ − f₂|.
  • Beat period is T_beat = 1/f_beat.
  • The approximate pitch of two nearby frequencies is related to their average frequency.
  • Musicians can tune instruments by listening for beats.
  • As two frequencies approach each other, the beats become slower.
  • When the frequencies match, the beats disappear.
  • Sound interference affects the amplitude and intensity heard at different locations.
  • Active noise cancellation uses destructive interference to reduce unwanted sound.
  • Acoustic engineers must consider interference when designing rooms and multi-speaker sound systems.
  • Beats and spatial interference are related through superposition but should not be confused: beats vary mainly with time, while spatial interference patterns vary with position.

Check Your Understanding

  1. State the principle of superposition.
  2. Explain the difference between constructive and destructive interference.
  3. Two identical waves each have an amplitude of 3.0 cm and arrive perfectly in phase. What is their resultant amplitude?
  4. Two waves with amplitudes of 7.0 cm and 5.0 cm arrive exactly opposite in phase. Calculate the magnitude of their resultant amplitude.
  5. Explain why two equal-amplitude waves 180° out of phase can completely cancel.
  6. Two tuning forks produce frequencies of 440 Hz and 446 Hz. Calculate the beat frequency.
  7. Two sound sources produce 256 Hz and 259 Hz. Calculate both the beat frequency and beat period.
  8. A musician hears 4 beats per second when comparing an unknown note with a 500 Hz reference. What are the two possible frequencies of the unknown note?
  9. Explain how the musician could determine which of the two possible frequencies in Question 8 is correct.
  10. Explain why the beat frequency decreases as a musical instrument approaches the correct tuning.
  11. A sound wave has a wavelength of 0.80 m. Determine the smallest non-zero path difference that would produce constructive interference and the smallest path difference that would produce destructive interference for two initially in-phase waves.
  12. Two equal-amplitude sound waves interfere constructively and produce twice the amplitude of either individual wave. How does the resulting intensity compare with the intensity of one wave?
  13. Explain how active noise-cancelling headphones use destructive interference and why perfect cancellation is difficult in a real environment.
  14. A student walks through a room containing two speakers producing the same frequency and hears alternating loud and quiet regions. Explain why this is an interference pattern rather than a beat pattern.
  15. Two musical instruments produce frequencies of 392 Hz and 395 Hz. Analyze what a listener would hear, calculate the beat frequency and beat period, and explain how a musician could use the observed beats to tune the instruments to the same frequency.